APhO 2013, theory — Задача 1

Автор: Olympiads XYZ · транскрипция на официалните материали

Проверена срещу оригинала на 15.9.2026 от независим модел

Съдържание

УсловиеРешение

Problem Conductors in Conducting Liquid

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14TH ASIAN PHYSICS OLYMPIAD BOGOR, INDONESIA Theory Question 1 page 1 of 1

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14TH ASIAN PHYSICS OLYMPIAD BOGOR, INDONESIA Theoretical 1: Solution Conductors in Conducting Liquid

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14TH ASIAN PHYSICS OLYMPIAD BOGOR, INDONESIA Theoretical 1: Solution Conductors in Conducting Liquid

[Source note]

14TH ASIAN PHYSICS OLYMPIAD BOGOR, INDONESIA Theoretical 1: Solution Conductors in Conducting Liquid

[Source note]

14TH ASIAN PHYSICS OLYMPIAD BOGOR, INDONESIA Theoretical 1: Solution Conductors in Conducting Liquid

[Source note]

14TH ASIAN PHYSICS OLYMPIAD BOGOR, INDONESIA Theoretical 1: Solution Conductors in Conducting Liquid

[Source note]

14TH ASIAN PHYSICS OLYMPIAD BOGOR, INDONESIA Theoretical 1: Solution Conductors in Conducting Liquid

Условие

A system consisted of two conductor bodies is immersed in a uniform dielectric and weakly conducting liquid. When a constant voltage difference is applied between both conductors, the system has both electric and magnetic fields. In this problem we will investigate this system.

  1. (0.4 pts) First consider an infinitely long line with charge per unit length λ\lambda in vacuum. Calculate the electric field E(r)\mathbf{E}(\mathbf{r}) due to the line.

  2. (0.4 pts) The potential due to the line charge could be written as

V(r)=f(r)+K,V(r) = f(r) + K, where KK is a constant. Determine f(r)f(r).

  1. (0.7 pts) Calculate the potential in all space V(x,y,z)V(x,y,z) due to an infinitely long line with charge per unit length λ\lambda at x=b,y=0x = -b, y = 0 and another infinitely long line with charge per unit length λ-\lambda at x=b,y=0x = b, y = 0. Both lines are parallel to the zz-axis. Take V=0V = 0 at the origin. Sketch the equipotential surfaces.

For the following questions, ignore any edge effects.

  1. (2.0 pts) Now consider two identical conducting cylinders, both with radius R=3aR = 3a in vacuum. The length of each cylinders are the same and much larger than its radius (lRl \gg R). The axis of both cylinders are on the xzxz-plane and parallel to the zz-axis, one at x=5ax = -5a, y=0y = 0 and the other at x=5ax = 5a, y=0y = 0. An electrical potential difference of V0V_0 is applied between the two cylinders (the cylinder at x=5ax = -5a has the higher potential) by connecting them to a battery. Calculate the potential in all regions. Take V=0V = 0 at the origin.

  2. (0.5 pts) Calculate the capacitance CC of the system.

  3. (1.0 pts) Now both cylinders are totally immersed in a weakly conducting liquid with conductivity σ\sigma. Calculate the total current that flows between both cylinders. Assume the permittivity of the liquid is equal to that of vacuum, ϵ=ϵ0\epsilon = \epsilon_0.

  4. (0.5 pts) Calculate the resistance RR of the system. Calculate RCRC of the system.

  5. (1.5 pts) Calculate the magnetic field due to the current in question 6. Assume that the permeability of the liquid is equal to that of vacuum μ=μ0\mu = \mu_0.

Решение

Покажи официалното решение

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Notes αdxα2+x2=arctanxa+const\int \frac{\alpha\,dx}{\alpha^2+x^2} = \arctan\frac{x}{a} + const

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Conductors in Conducting Liquid Page 1 of 6

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Conductors in Conducting Liquid Page 2 of 6

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Conductors in Conducting Liquid Page 3 of 6

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Conductors in Conducting Liquid Page 4 of 6

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Conductors in Conducting Liquid Page 5 of 6

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Conductors in Conducting Liquid Page 6 of 6

Теми и трудност

Трудност: неоценена.

Електричество · Магнетизъм и индукция · Електростатика · Електрично поле · Електричен потенциал · Закон на Гаус · Кондензатори и диелектрици · Ток и съпротивление · Магнитно поле · Закони на Ампер и Био–Савар


Оригинал в Архива: 1.pdf · официални решения: 1_sol.pdf