APhO 2023, theory — Задача 1. Theoretical Problem 1: ISS Orbital Decay Dynamics [10.0 points]

Автор: Olympiads XYZ · транскрипция на официалните материали

Проверена срещу оригинала на 13.9.2026 от същия модел, който я е транскрибирал (без независима проверка)

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УсловиеРешение

Theory — XXIII APhO Mongolia 2023 — Theoretical Problem 1: ISS Orbital Decay Dynamics [10.0 points] · 10 т.

Внимание: Бележка към темата

Transcribed from a partial window (solutions pages 1–6 of 9); the problem statement and the remaining solution pages are covered by other windows.

Условие

Introduction

Figure 1: The International Space Station orbiting above the Earth.

The ISS is currently maintained in a nearly circular orbit with a minimum mean altitude of 370km370\,km and a maximum of 460km460\,km, in the center of the thermosphere, at an inclination of θ=51.6\theta = 51.6^{\circ} (degrees) to Earth's equator. The trajectory of the spacecraft is similar to a spiral with a slowly changing distance from the station to the Earth's surface, and during one cycle of revolution the change in altitude is inconsiderable.

The ISS mass is MS=4.5×105kgM_S = 4.5 \times 10^{5}\,kg and overall length is LS=109mL_S = 109m. Huge solar panels with a width of WS=73mW_S = 73m provide the ISS with electrical energy [NASA Official Report (2023)].

Including all batteries and other parts, the effective cross area (section) of the station is approximately S2.5×103m2S \approx 2.5 \times 10^{3}\,\mathrm{m}^2 [European Space Agency, SDC6-23].

The ISS orbital decay is caused by one or more mechanisms which absorb energy from the orbital motion, the essential ones being:

  • atmospheric drag at orbital altitude is caused by frequent collisions of gas molecules with the satellite,
  • the Ampere force arising from the motion of the conductive apparatus in the Earth's magnetic field,
  • the interaction with the atomic oxygen ions.

"... In May 2008, the altitude was 350 kilometers, the ISS lost 4.5km4.5km and was re-boosted by the Progess-60 supply ship by 5.5km5.5km. Again, the ISS continued to lose altitude by 5.5km5.5km ..." [https://mod.jsc.nasa.gov]

Figure 2: The altitude of ISS (kmkm) over the years.

Figure 3: The ISS mean height (kmkm) in 2022-2023.

". . . The ISS loses up to 330ft330ft ( 100m100m) of altitude each day . . . " [NASA Control Data (2021)]. In 2023 the ISS flies at altitudes of 410 km, with an orbital decay about 70m70m every day ( 2km\sim 2km per month), and during magnetic storms the daily descent reaches 300m300m. The ISS accomplishes the de-orbit maneuvers by using the propulsion capabilities of the ISS and its visiting vehicles [International Space Station Transition Report (2022)].

Figure 4: ISS model with the cross sections from different aspect angles (dm2dm^2). The CROC provides 2481m22481m^2 cross section.

Denotations and Physical constants:

Universal gas constantRR=8.31JK1mol1= 8.31\,J\cdot K^{-1}\cdot mol^{-1}
Avogadro's numberNAN_A=6.0221023mol1= 6.022\cdot 10^{23}\,mol^{-1}
The molar mass of gas (for air)μ\mu=0.029kgmol1= 0.029\,kg\cdot mol^{-1}
Mass of the EarthMEM_E=5.971024kg= 5.97\cdot 10^{24}\,kg
Radius of the EarthRER_E=6.38106m= 6.38\cdot 10^{6}\,m
Gravitational universal constantGG=6.671011m3s2kg1= 6.67\cdot 10^{-11}\,m^3\cdot s^{-2}\cdot kg^{-1}
Density of air at Earth's surfaceρ0\rho_0=1.29kg/m3= 1.29\,kg/m^{3}
Gravitational acceleration at Earth's surfaceg0g_0=9.81ms2= 9.81\,m\cdot s^{-2}
Average magnitude of Earth's magnetic fieldBB=5.0105T= 5.0\cdot 10^{-5}\,T
The electron absolute chargeee=1.601019C= 1.60\cdot 10^{-19}\,C

Part A: Modified barometric formula [2.0 points]

The pressure of atmospheric air, composed mainly of neutral O2O_2 and N2N_2 molecules, can be found by using the Clapeyron-Mendeleev law (the ideal gas law): pV=MμRTpV = \frac{M}{\mu}RT. where p,V,T,Mp,V,T,M and μ\mu are the pressure, volume, temperature, mass and molar mass of a portion of air, RR is the ideal gas universal constant.

There are two equations for computing air pressure as a function of height. The first equation is applicable to the standard model of the troposphere (h<100kmh < 100km) in which the temperature is assumed to vary with altitude at a lapse rate.

The second equation belongs to the standard model of the thermosphere (h>250kmh > 250km) in which the temperature is assumed not to change considerably with altitude and is applicable to ISS.

We may assume that all pressure is hydrostatic and isotropic (i.e., it acts with equal magnitude in all directions).

Remark 1. The temperature of Earth's thermosphere at altitude 300600km300-600\,km does not change considerably and reaches averagely about 800900K800-900\,K on the solar side [NASA data]. Therefore, one may put Th=T=constT_h = T = const by investigating the ISS orbital flight. Particularly, since the spacecraft spends almost half of its flight time in the shadow side of the Earth, where the temperature drops sharply, we may take the value of T=425KT = 425K as the average temperature at these altitudes. This temperature is also in agreement with the air density value ρh1012kg/m3\rho_h \sim 10^{-12}kg/m^3 [MSISE-90 Model of Earth's Upper Atmosphere] at h=400kmh = 400km.

Figure 5: The Earth's thermosphere.

Part B: Orbital deceleration and station descent rate [3.0 points]

Let us consider the problem of determining the rate of orbital decay of a satellite with mass MSM_S that experiences constant friction force Fdrag\vec{F}_{drag} acting on it. We assume that the decrease in altitude dhdh is much less than the flight altitude hh itself (dhhdh \ll h).

Part C: Atmospheric drag [1.0 points]

The speed of the satellite vv is many times greater than the average velocities (hundreds m/s) of the thermal motion of atmospheric molecules at a height h300400kmh \approx 300 - 400km, so we can assume that the molecules were at rest before the collision with the ISS. To roughly estimate the drag force, we assume that after the collision the molecules acquire the same speed as the satellite.

Part D: Drag by atomic oxygen ion [1.0 points]

In the thermosphere, under the influence of ultraviolet and X-ray solar radiation and cosmic radiation, air ionization occurs (``polar lights''). Unlike O2O_2, N2N_2 does not undergo strong dissociation under the action of solar radiation, therefore, in general, there is much less atomic nitrogen NN in the Earth's upper atmosphere than atomic oxygen. At altitudes above 250km250km, atomic oxygen OO predominates. Layers containing electrons and ions of oxygen atoms appear on the day side of the atmosphere. In this case, the concentration of atomic oxygen ions reaches nion1012m3n_{ion} \sim 10^{12}m^{-3}

Part E: Drag by the Earth's magnetic field [2.0 points]

We consider the influence on the motion of the satellite of the Earth's magnetic field, the value of which near the Earth's surface is equal to (3.56.5)105T(3.5 - 6.5)\cdot 10^{-5}T with an average value of B=5105TB = 5\cdot 10^{-5}T.

When a satellite moves at high speed in a magnetic field, an inducted electric current (electromotive force (EMF) ) occurs in the current-conducting elements of the satellite's structure. This electromotive force causes a redistribution of electric charges in the current-conducting elements of the satellite structure. An electric field appears around the satellite, which affects the movement electrically charged particles in the environment. Electrons are attracted to those parts of the satellite that have a positive potential (relative to the middle part of the satellite), and positively charged ions are attracted to those parts of the satellite that have a negative potential. Electrons and ions that hit the surface of the satellite structures are combined into neutral oxygen atoms, while the electrons 'travel' in the satellite's conductive structures, creating an electric current. The satellite, moving in space, 'collects' electrons and ions from the surrounding space and collides with them. For a rough estimate of the magnitude of the current that can flow through the conductive structures of the satellite, we will assume that the collection occurs only from an area equal to the cross-sectional area SS of the satellite, and all ions and electrons participate in the creation of this current.

Part F: Numerical results and conclusion [1.0 points]

F.2 Calculate and fill Table 2 in the Answer Sheet. [0.4pt] F.3 Rank these three orbital slowing processes in order of how strong an impact they have on ISS orbital altitudes higher than 380km380km. For the International Space Station, orbiting at an altitude above 380km380km, write down the most significant factors contributing to orbital decay. [0.2pt]

Photograph of the International Space Station with its large solar panels against the dark sky, with the blue curvature of the Earth below.
Figure 1: The International Space Station orbiting above the Earth.
Noisy line plot of ISS altitude (km) from 1998 to 2018, y-axis 300–440 km, showing sawtooth decay with re-boosts, rising to about 410–420 km after 2012.
Figure 2: The altitude of ISS (km)(km) over the years.
Line plot titled 'ISS - mean height in km', May 2022 to May 2023, y-axis 415–420 km, sawtooth pattern of decay and re-boosts.
Figure 3: The ISS mean height (km)(km) in 2022-2023.
Scatter plot of cross-section (color scale 50000–450000) versus azimuth (−150 to 150 deg) and elevation (−80 to 80 deg), with symmetric colored dots; a color bar is at the right.
Figure 4: ISS model with the cross sections from different aspect angles (dm2)(dm^2). The CROC provides 2481m22481m^2 cross section.
Diagram of Earth's atmosphere layers (Troposphere, Stratosphere, Mesosphere, Thermosphere) with a temperature scale (100–1200 K), solar radiation bands (X-Rays, Extreme UV, Far UV, Middle UV, Near UV, Visible and IR), IR Cooling, and a density scale (log10 n, cm-3, 4–20) with curves for O2, N2, O, He, H and electron density.
Figure 5: The Earth's thermosphere.

A.1 Derive the general integral expression for the air pressure php_h at ISS altitude hh. This equation is called the general barometric formula. Hint: the temperature and gravitation may depend on hh. [0,5 т.]

A.2 Write down the air pressure (the standard barometric formula) phstap_h^{sta}, when the temperature and gravitation ghg_h do not depend on hh. Calculate the parameter h0=RTμg0h_0 = \frac{RT}{\mu g_0} for T=425KT = 425K. [0,3 т.]

A.3 Write down the air pressure (the improved barometric formula) phimpp_h^{imp} when the temperature is constant but the gravitation depends on hh. Hint: Use the leading-order correction only, with accuracy O(zh2)O(z_h^2). Hereby, the flight altitude hh above the Earth's surface is significantly smaller than the Earth's radius: zhh/RE1z_h \doteq h/R_E \ll 1. [0,6 т.]

A.4 Write down the ratio of the 'standard' and 'improved' versions of the barometric formula phimp/phstap_h^{imp}/p_h^{sta}. Estimate it for h=4.0×105mh = 4.0 \times 10^{5}m. Further use the 'improved' version. [0,4 т.]

A.5 Write down the air density ρh\rho_h and the concentration of neutral air molecules nhn_h at height hh, with accuracy O(zh2)O(z_h^2). [0,2 т.]

B.1 Write down the satellite velocity vhv_h and revolution period τh\tau_h on a stable orbit of altitude hh. [0,5 т.]

B.2 Write down the total energy ESE_S of a satellite moving along a circular orbit with radius RE+hR_E + h. [0,5 т.]

B.3 The total decelerating force exerted on a satellite of constant mass is given by some external braking force Fdrag\vec{F}_{drag}. As a result, the ISS slows down and its altitude decreases by a height dhdh for a small time interval, dtdt. Write down the equation for the total enery balance of the ISS and surrounding system, given a value of FdragF_{drag}. [1 т.]

B.4 Define the rate of descent (de-orbiting ) speed uhu_h of the satellite. Hint: The de-orbiting speed depends on the friction force, and on the altitude of the satellite, and on the mass of the satellite. [0,5 т.]

B.5 Write down the amount of decent HhH_h for a revolution around the Earth and the total time ThT_h for which the satellite will fall from the altitude hh to the earth's surface due to the friction. Hint: Take into account relations h0hREh_0 \ll h \ll R_E. [0,5 т.]

C.1 Write down the air drag force FairF_{air}, the de-orbiting descending velocity uhairu_h^{air} and the descent rate HhairH_h^{air}. [0,5 т.]

C.2 Define the total time ThairT_h^{air} for which the satellite will fall from the altitude hh to the earth's surface due to air drag effect. Hint: Take into account relations h0hREh_0 \ll h \ll R_E. [0,5 т.]

D.1 Write down the decelerating force FionF_{ion}, averaged during a 24-hour, associated with the mechanical collisions of these particles. Take into account the strong decrease in ionized layers are negligible during the night. Express the density of ionized oxygen molecules ρion\rho_{ion}. [0,3 т.]

D.2 Define the speed of fall of the satellite uhionu_h^{ion} due to deceleration by ions of atomic oxygen. Write down the descent rate HhionH_h^{ion} for a revolution caused by the ionization effect. Hint: Take into account relations h0hREh_0 \ll h \ll R_E. [0,7 т.]

E.1 Evaluate approximately the magnitude of the induced electric current IindI_{ind}. [0,6 т.]

E.2 Determine an approximate expression for the induced 'braking' Ampere force FindF_{ind} in the direction opposite to the direction of the satellite's motion. Let ϕ\phi be the angle between the Earth magnetic field BB along the longitude lines. To simplify, you may approximate the length of the satellite LL as the square root of the satellite area SS. Additionally, instead of computing the average of sin(ϕ)\sin(\phi), you may approximate it with sin(π/2θ)\sin(\pi/2 - \theta). You may use a discrete number of sample points to compute an average value. [0,6 т.]

E.3 Write down the descent speed uindu_{ind} of the satellite due to Earth's magnetic field. Write down the descent rate HhindH_h^{ind} for a revolution caused by the magnetic drag effect. Hint: Take into account relations hREh \ll R_E. [0,8 т.]

Решение

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Оригинал в Архива: T1.pdf · официални решения: T1_sol.pdf