IAO 2009, Теория, Група α — Задача 5. Mirror for a telescope.
Theoretical round. Problems to solve · 8 ноември 2009 г.
Бележка
Maybe not all problems have correct questions. Some questions (maybe the main question of the problem, maybe one of the subquestions) may have no real sense. In this case you have to write in your answer (in English or Russian): “impossible situation – ситуация невозможна”. Of course, this answer has to be explained numerically or logically.
Data from the table of planetary data may be used for solving every problem.
The answers «Да-Yes» or «Нет-No» has to be written in English or Russian.
Note for jury and team leaders.
The proposed sketches are not full: the team leaders have to give more detailed explanations for students. But the correct solutions in the students’ papers (enough for 8 pts) may be shorter.
Parameters of orbits. Physical characteristics of some planets, Moon, Sun and Eris
| Body, planet | Average distance (astr. units) | Average distance (mln. km) | Sidereal period (troph. years) | Period (days) | Eccentricity | Equat. diameter (km) | Mass ( kg) | Av. density (g/cm³) | Grav. acceler. (m/s²) | Max. magn. from Earth | Albedo |
|---|---|---|---|---|---|---|---|---|---|---|---|
| Sun | 1392000 | 1989000 | 1.409 | ||||||||
| Mercury | 0.387 | 57.9 | 0.241 | 87.97 | 0.206 | 4879 | 0.3302 | 5.43 | 3.70 | 0.06 | |
| Venus | 0.723 | 108.2 | 0.615 | 224.70 | 0.007 | 12104 | 4.8690 | 5.24 | 8.87 | 0.78 | |
| Earth | 1.000 | 149.6 | 1.000 | 365.26 | 0.017 | 12756 | 5.9742 | 5.515 | 9.81 | 0.36 | |
| Moon | 0.00257 | 0.38440 | 0.0748 | 27.3217 | 0.055 | 3475 | 0.0735 | 3.34 | 1.62 | 0.07 | |
| Mars | 1.524 | 227.9 | 1.880 | 686.98 | 0.093 | 6794 | 0.6419 | 3.94 | 3.71 | 0.15 | |
| Jupiter | 5.204 | 778.6 | 11.862 | 4332.59 | 0.048 | 142984 | 1899.8 | 1.33 | 24.86 | 0.66 | |
| Saturn | 9.584 | 1433.7 | 29.458 | 10759.20 | 0.054 | 120536 | 568.50 | 0.70 | 10.41 | 0.68 | |
| Eris | 68.01 | 204862 | 0.434 | 2600 | 0.0167 | 0.8 | 0.86 |
**) For Moon: in mean opposition.
Some constants and formulae
| Constant or formula | Value |
|---|---|
| Speed of light in vacuum, (m/s) | 299792458 |
| Constant of gravitation, (N·m²/kg²) | |
| Solar constant, (W/m²) | 1367 |
| Hubble constant, (km/s/Mpc), mean value | 70 |
| Hubble constant, diapason of values | 50–100 |
| Plank constant, (J·s) | |
| Charge of electron, (C) | |
| Mass of electron, (kg) | |
| Proton-to-electron ratio | 1836.15 |
| Faraday constant, (C/mol) | 96485 |
| Magnetic constant, (H/m) | |
| Universal gas constant, (J/mol/K) | 8.314 |
| Boltzmann constant, (J/K) | |
| Standard atmosphere (Pa) | 101325 |
| Stefan-Boltzmann constant, (W/m²/K⁴) | |
| Wien's displacement constant, (m·K) | 0.002897 |
| Laboratory wavelength of H (Å) | 6563 |
| Refractive index of water for20°C, | 1.334 |
| Area of sphere | |
| 3.14159265 |
Data of some stars
| Star | Designation | RA | DEC | m | SC |
|---|---|---|---|---|---|
| Arcturus | Boo | -0.05 | K1 | ||
| Vega | Lyr | 0.03 | A0 | ||
| Deneb | Cyg | 1.25 | A2 | ||
| Polaris | UMi | 2.02 | F7 | ||
| Sirius | CMa | -1.46 | A1 |
Бележки от източника
The original two-up official key photographs clip some right-hand line endings. Ellipses mark those unreadable endings; visible formulae and printed numerical values are retained. The reference table gives the Eris period as 204862 days, whereas the key uses 204852 days. Original inline slash notation is retained in the key. The photographed alpha masthead is cropped, but the original filename and distinct alpha tasks in the official key establish its group.
Условие
You have a disc of glass with thickness , from which one has to make (by grinding) a spherical mirror with a diameter of . What could the focal distances be of a mirror made from this disc?
Решение
Внимание: Непълно решение
The original official key photograph clips several right-hand line endings. All visible text, formulae and diagrams are retained; ellipses mark unreadable source endings.
It is evident that the depth “x” in the centre of the disc must be less than th… thickness . Let be the curvature radius of the mirror. It means (from the Pythagorean theorem… that the minimum is defined by the equation:

The relation between the focal length and the curvature radius o… the mirrow is , i.e. for zero thickness in the centre of the dis…
So, theoretically the focal length may be in the interval from 401 mm to infinity. Nevertheless, th… thickness in the centre of the disc cannot be zero, let us take it at least 2 mm. In this case we should us… instead of
The focal length may be in the interval from about 420 mm to infinity.
Оригинал в Архива: alphatheo.png · допълнителни данни: theosol1.jpg · допълнителни данни: theosol2.jpg · допълнителни данни: constants.jpg