IAO 2018, Теория, α+β — β-2. Martian observations
XXIII International Astronomy Olympiad — Theoretical round, α and β · 6 октомври 2018 г. · 8 т.
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General note. Maybe not all problems have correct questions. Some questions (maybe the main question of the problem, maybe one of the subquestions) may make no real sense. In this case you have to write in your answer (in English): «impossible situation». Of course, this answer has to be explained numerically or logically.
Data from the tables (Planetary data, stars, constants, etc.) may be used for solving every problem.
The answers «Yes» or «No» have to be written in English.
Do not forget that in clean copy you should write solutions only on even (left) pages. The odd (right) pages will be used by your team leader to translate solutions into English and also to emphasize your thoughts in solutions.
Parameters of orbits and physical characteristics of Sun, planets, some dwarf planets and Moon
| Body, planet | Average distance to central body (astr. units) | Distance (mln. km) | Sidereal period (tropical years) | Period (days) | Eccentricity e | Equatorial diameter (km) | Mass (10²⁴ kg) | Average density (g/cm³) | Gravity at surface (m/s²) | Max. magnitude from Earth | Albedo |
|---|---|---|---|---|---|---|---|---|---|---|---|
| Sun | 1.6·10⁹ | 2.5·10¹¹ | 2.2·10⁸ | 8·10¹⁰ | 1392000 | 1989000 | 1.409 | −26.8ᵐ | |||
| Mercury | 0.387 | 57.9 | 0.241 | 87.969 | 0.206 | 4879 | 0.3302 | 5.43 | 3.70 | −2.2ᵐ | 0.06 |
| Venus | 0.723 | 108.2 | 0.615 | 224.701 | 0.007 | 12104 | 4.8690 | 5.24 | 8.87 | −4.7ᵐ | 0.78 |
| Earth | 1.000 | 149.6 | 1.000 | 365.256 | 0.017 | 12756 | 5.9742 | 5.515 | 9.81 | 0.36 | |
| Moon | 0.00257 | 0.38440 | 0.0748 | 27.3217 | 0.055 | 3475 | 0.0735 | 3.34 | 1.62 | −12.7ᵐ | 0.07 |
| Mars | 1.524 | 227.9 | 1.880 | 686.980 | 0.093 | 6794 | 0.6419 | 3.94 | 3.71 | −2.0ᵐ | 0.15 |
| Ceres | 2.77 | 414 | 4.60 | 1681 | 0.077 | 963 | 0.0009 | 2.16 | 0.27 | 6.7ᵐ | 0.09 |
| Jupiter | 5.204 | 778.6 | 11.862 | 4332.59 | 0.048 | 142984 | 1899.8 | 1.33 | 24.86 | −2.7ᵐ | 0.66 |
| Saturn | 9.584 | 1433.7 | 29.458 | 10759.20 | 0.054 | 120536 | 568.50 | 0.70 | 10.41 | 0.7ᵐ | 0.68 |
| Uranus | 19.191 | 2871.0 | 84.015 | 30685.93 | 0.046 | 51118 | 86.625 | 1.30 | 8.44 | 5.5ᵐ | 0.74 |
| Neptune | 30.071 | 4498.6 | 164.778 | 60187.64 | 0.008 | 49532 | 102.78 | 1.76 | 11.20 | 7.8ᵐ | 0.58 |
| Pluto | 39.482 | 5906.4 | 248.09 | 90613 | 0.249 | 2374 | 0.0130 | 1.86 | 0.61 | 15.1ᵐ | 0.6 |
For outer planets and Moon — in mean opposition.
| Coordinates | Hotel | Seafront in the center |
|---|---|---|
| λ (E) | 79°52′ | 79°51′ |
| φ (N) | 07°00′ | 06°54′ |
| Timezone | UT+05:30 | UT+05:30 |
Some constants and formulae
| Quantity | Value |
|---|---|
| Speed of light in vacuum, c (m/s) | 299792458 |
| Constant of gravitation, G (N·m²/kg²) | 6.674·10⁻¹¹ |
| Solar constant, A (W/m²) | 1367 |
| Hubble parameter, H₀ (km/s/Mpc): mean value | 68 |
| Hubble parameter: diapason of values | 50–100 |
| Planck constant, h (J·s) | 6.626·10⁻³⁴ |
| Charge of electron, e (C) | 1.602·10⁻¹⁹ |
| Mass of electron, mₑ (kg) | 9.109·10⁻³¹ |
| Proton-to-electron mass ratio | 1836.15 |
| Faraday constant, F (C/mol) | 96485 |
| Magnetic constant, μ₀ (H/m) | 1.257·10⁻⁶ |
| Universal gas constant, R (J/mol/K) | 8.314 |
| Boltzmann constant, k (J/K) | 1.381·10⁻²³ |
| Stefan-Boltzmann constant, σ (W/m²/K⁴) | 5.670·10⁻⁸ |
| Wien’s displacement constant, b (m·K) | 0.002897 |
| Laboratory wavelength of Hα (Å) | 6563 |
| Laboratory wavelength of Hβ (Å) | 4861 |
| Tropical year length, T (days) | 365.242199 |
| Sidereal year length, T (days) | 365.25636 |
| Anomalistic year length, T (days) | 365.259636 |
| Nodal period of lunar orbit (years) | −18.6 |
| Standard pressure (Pa) | 101325 |
| Visible light extinction by the terrestrial atmosphere in zenith (minimum) | 19%, 0.23ᵐ |
| Height of homogeneous atmosphere (m) | 7991 |
| Refractive index of water for 20°C, n | 1.334 |
| Moment of inertia of solid ball | |
| Moment of inertia of sphere | |
| Volume of a ball | |
| Area of sphere | |
| π | 3.14159265 |
| e | 2.71828183 |
| Golden ratio, φ | 1.61803399 |
Theoretical round. Basic criteria. For work of Jury
Note. The given sketches of solutions are not full; the team leaders have to give more detailed explanations to students. The correct solutions in the students’ papers (enough for 8 pts) may be shorter.
Note. Jury members should evaluate the student’s solutions in essence, and not by looking on formal existence the mentioned sentences or formulae. The formal presence of the mentioned positions in the text is not necessary to give the respective points. Points should be done if the following steps de facto using these positions.
Note. Jury members should elaborate more detailed criteria, and also create criteria for other correct ways of the student’s solutions.
Printed source discrepancies
The galaxy key prints nm for the wavelengths 6563 and 4861, while the constants sheet gives Å. The Martian key reverses the question’s subpart order, prints a lunar-radius term 0.17·10⁵ km, and reuses L₂ for the semimajor axis. The satellite key calls R a diameter and prints 10h20m after subtracting 62 minutes from 11h12m. Printed formulas and labels are retained rather than silently corrected. The satellite key refers to a drawing absent from the supplied solution packet.
Условие
In July this year, within one day, two unique astronomical phenomena occurred. In the morning of July 27, Mars came into a great opposition (see the attached ephemeris), and in the evening, the inhabitants of the Earth (those lucky with the weather and geographical location) observed a long lunar eclipse. But the rapprochement of the Earth and Mars is also a good time for Martian astronomers to study the Earth and The Moon. The Martian Space Agency planned two expeditions to the near-Mars piloted orbital station to observe:

2.1.
transit of the Earth across the disk of the Sun (it is assumed that the entire disk of the Earth must pass at least along the edge of the Sun) to study the atmosphere of the Earth;
2.2.
transit of the Moon across the disk of the Earth (it is assumed that the entire disk of the Moon must pass over the disk of the Earth) to study the lunar atmosphere.
For each of these observations, determine in which constellation the objects will be observed from Mars, whether the orbital expedition is feasible (write “Yes” or “No” in English), and if so, find the minimum orbital period of Martian orbital station of the expedition, and if not, prove it by making the necessary calculations and drawings.
Решение
Martians will observe the Sun, the Earth and the Moon in the constellation opposite to that in which we observe the full Moon and the opposition of Mars in the end of July. That is, this is exactly the constellation in which at the end of July the Sun is located for observers at the Earth. In the constellation of Cancer.
2.1.
Using the data of the ephemeris, we can interpolate the values of the right ascension and declination of the Moon and Mars at the time of the mid-point of the lunar eclipse. For the Moon, we obtain , . For Mars at the same time — , . We see that the difference in right ascensions is negligible compared with the difference in declinations, therefore the angular distance between the centers of the Moon and Mars at this time with great accuracy will be .
The center of the moon will be at a distance
from the line connecting the centers of Mars and Earth, and the northern edge of the Moon is at a distance
from the line connecting the center of Mars and the northern edge of the Earth. The angle between the line connecting the northern points of the Earth and the Moon, and the line connecting the centers of Mars and Earth, will be
Thus, to observe the transit of the entire disk of the Moon across the disk of the Earth, the Martian orbital station must be at a distance
from the center of Mars. This means that the orbital station must have a semi-major axis of the orbit equal to at least
Orbiting of bodies around Mars in orbit with such a large semi-axis is impossible, such an orbit goes beyond Hill’s sphere.
2.2.
This part of the problem is solved similarly to the previous one. In order to observe the passage of the Earth along the solar disk, the Martians must hit a point that is directly opposite to the position of the center of the Sun for the earth observer (with an accuracy of the angular radius of the Sun seen from Mars). From the ephemeris of the Sun, we see that at the time of the Mars opposition, the declination of such a point is approximately . For Mars, this value is . The angular distance between the desired point and Mars at this time with high accuracy will be . With a correction for the angular radius of the Sun, the minimum angle required for Martians from Mars will be .
Thus, in order to observe the passage of the Earth across the disk of the Sun, the Martian orbital station must be at a distance
from the center of Mars. This means that the orbital station must have a semi major axis of the orbit equal to at least
Orbiting of bodies around Mars in orbit with such a large semi-axis is impossible, such an orbit goes beyond Hill’s sphere.
Basic criteria
| Item | Points |
|---|---|
| Correct constellation | 1 |
| Formulae, calculation distance from Mars for the first expedition | 1 |
| Formulae, calculation distance from Mars for the second expedition | 1 |
| Formulae, calculation theoretical periods of orbital stations | 1 |
| Solution with possibility to send orbital station | max. 4 |
| Formulae, calculations and issue about impossibility to send orbital station | 3 |
| Formulae, calculation diameter of Hill sphere | 1 |
Оригинал в Архива: theo.pdf · официални решения: theosol.pdf · допълнителни данни: iao2018_alpha.pdf