IdPhO 2020, Теория — Задача 1B. Part B. Suspension in magnetic field
Theory — IdPhO 2020 — Q1 — Problem mix (10 points) · 3 т.
Условие
Part B. Suspension in magnetic field (3 points)
B.1 A current flows through a loop made of a weightless flexible wire. The loop upper point is attached to the ceiling and a weight is suspended to its lowest point. The half length of the loop is . The loop is placed in a vertical magnetic field . The system has reached a stable equilibrium in which the point of suspension at the ceiling and the point of weight suspension are not on the same vertical. Find the wire tension and the weight if the distance from the ceiling to the lowest point of the loop is . [3 т.]

Отговори
- B.1
Решение
First approach
The Ampere's force acting on a short piece of wire of length is
The net force acting on this piece is
Here and are tension force of the wire acting on the two end points of the piece.
Projected on the , this equation reads:
Therefore, the tension is constant along the wire.
Let be the tangent vector of the wire at the distance from the point of suspension. The equation (1) reads
This equation implies that
The tangent vector of the wire is at constant angle to the magnetic field. In the horizontal plane the tangent vector is rotating at a constant speed. Thus, each side of the loop has the cylindrical helix shape, i. e. it is winding around some cylinder and making the constant angle to the magnetic field. To find the radius of this cylinder, let's write the equation in the projection on the horizontal plane:
At the point of the weight suspension we have the balance between three forces: two forces of tension(from each side of the loop) and the gravitational force of the weight, which is vertical. These three forces should be in the same vertical plane. Therefore, both sides of the loop are winding around the same cylinder. Each half of the loop should make a half-turn around this cylinder.
Thus, the length of the half of the loop is
Therefore,
The tension force of the wire can be found from equations (2) and (3)
The suspended weight is
Second approach
Stable equilibrium corresponds to a minimum of potential energy. The potential energy is a sum of the gravitational energy of the weight and of the energy of the loop in the magnetic field. Let be an area of the loop projected on the horizontal plane.
depends on two variable parameters: and . Note that we can change the form of the projection (not changing its length) of the loop onto horizontal plane without changing . Thus, the minimum of the potential energy corresponds to the maximum area of the projection with fixed length — a circle.
Now, if the projection is fixed, the height is maximal if the wire makes a constant angle with the vertical axis. Thus, the wire has a shape of cylindrical helix — each side is winding a cylinder, while making constant angle with vertical axis.
Let be the radius of the cylinder.
Then
The condition for the minimum of the potential energy is
The force balance equation at the point of weight suspension:
Оригинал в Архива: IPhO_2020_Q1.pdf · официални решения: IPhO_2020_S1.pdf