INPhO 2026, Теория — Задача 3. Slow, smooth, and sudden

Indian National Physics Olympiad (INPhO)-2026 · Question Paper · 1 февруари 2026 г. · 11 т.

Внимание: Бележка към темата

Matching original question and official key booklets are retained in full. The separate blank Answer Booklet, Summary Answersheet copies and blank graph paper referred to in the questions are absent from the archive; the supplied completed Kepler/glass answer-sheet illustrations remain in the key. Native question pages7 and9 are blank. Question6 says photographs on the next page although its photos occur on native p10 after blank p9. Printed source errors/conventions are preserved and attributed locally: P2 negative dM followed by positive boxed dUm and changing absolute-work notation; P3 Qa=-W followed by positive released heat, dropped-mass wording and P0/V0 notation; P4 derivative/height signs, c/cs and time-delay description; P5 intermediate phiP versus final phiC, log log and r/logarithm numerical scales. The graph/grid pixels and printed fitted results are source data, not newly calculated measurements.

Question booklet · Instructions and Table of Constants

Indian National Physics Olympiad (INPhO)-2026

HOMI BHABHA CENTRE FOR SCIENCE EDUCATION · Tata Institute of Fundamental Research · V. N. Purav Marg, Mankhurd, Mumbai, 400 088

Question Paper

Date: 01 February 2026 · Time: 09:00–12:00 (3 hours) · Maximum Marks: 75

Roll Number: □□□□ – □□□□ – □□□□

Instructions

  1. This booklet consists of 10 pages and total of 6 questions. Write roll number at the top wherever asked.
  2. Booklet to write the answers is provided separately. Instructions to write the answers are on the Answer Booklet.
  3. Non-programmable scientific calculators are allowed. Mobile phones cannot be used as calculators.
  4. Take as many data points as possible for the analysis.
  5. Please submit the Answer Sheet at the end of the examination. You may retain the Question Paper.
  6. Except for writing your roll number, no rough work or scribbling is allowed on the question paper.

Table of Constants

QuantitySymbolValue
Speed of light in vacuumcc3.00×108 m⋅s−13.00\times10^8\ \mathrm{m\cdot s^{-1}}
Magnitude of electron chargeee1.60×10−19 C1.60\times10^{-19}\ \mathrm C
Avogadro’s numberNAN_A6.022×1023 mol−16.022\times10^{23}\ \mathrm{mol^{-1}}
Acceleration due to gravitygg9.81 m⋅s−29.81\ \mathrm{m\cdot s^{-2}}
Universal Gas ConstantRR8.31 J⋅K−1⋅mol−18.31\ \mathrm{J\cdot K^{-1}\cdot mol^{-1}}
RR0.0821 l⋅atm⋅mol−1⋅K−10.0821\ \mathrm{l\cdot atm\cdot mol^{-1}\cdot K^{-1}}
Boltzmann constantkBk_B1.3806×10−23 J⋅K−11.3806\times10^{-23}\ \mathrm{J\cdot K^{-1}}
Permeability constantμ0\mu_04π×10−7 H⋅m−14\pi\times10^{-7}\ \mathrm{H\cdot m^{-1}}
One Atmospheric pressureatm1.013×105 Pa1.013\times10^5\ \mathrm{Pa}
Question Number123456Total
Maximum Marks12121110181275
Solution booklet · Instructions, constants and alternate-method note

Indian National Physics Olympiad (INPhO)-2026

HOMI BHABHA CENTRE FOR SCIENCE EDUCATION · Tata Institute of Fundamental Research · V. N. Purav Marg, Mankhurd, Mumbai, 400 088

Question Paper

Date: 01 February 2026 · Time: 09:00–12:00 (3 hours) · Maximum Marks: 75

Roll Number: □□□□ – □□□□ – □□□□

Instructions

  1. This booklet consists of 21 pages and total of 6 questions. Write roll number at the top wherever asked.
  2. Booklet to write the answers is provided separately. Instructions to write the answers are on the Answer Booklet.
  3. Non-programmable scientific calculators are allowed. Mobile phones cannot be used as calculators.
  4. Take as many data points as possible for the analysis.
  5. Please submit the Answer Sheet at the end of the examination. You may retain the Question Paper.
  6. Except for writing your roll number, no rough work or scribbling is allowed on the question paper.

Table of Constants

QuantitySymbolValue
Speed of light in vacuumcc3.00×108 m⋅s−13.00\times10^8\ \mathrm{m\cdot s^{-1}}
Magnitude of electron chargeee1.60×10−19 C1.60\times10^{-19}\ \mathrm C
Avogadro’s numberNAN_A6.022×1023 mol−16.022\times10^{23}\ \mathrm{mol^{-1}}
Acceleration due to gravitygg9.81 m⋅s−29.81\ \mathrm{m\cdot s^{-2}}
Universal Gas ConstantRR8.31 J⋅K−1⋅mol−18.31\ \mathrm{J\cdot K^{-1}\cdot mol^{-1}}
RR0.0821 l⋅atm⋅mol−1⋅K−10.0821\ \mathrm{l\cdot atm\cdot mol^{-1}\cdot K^{-1}}
Boltzmann constantkBk_B1.3806×10−23 J⋅K−11.3806\times10^{-23}\ \mathrm{J\cdot K^{-1}}
Permeability constantμ0\mu_04π×10−7 H⋅m−14\pi\times10^{-7}\ \mathrm{H\cdot m^{-1}}
One Atmospheric pressureatm1.013×105 Pa1.013\times10^5\ \mathrm{Pa}
Question Number123456Total
Maximum Marks12121110181275

Please note that alternate/equivalent methods and different ways of expressing final solutions may exist. A correct method will be suitably awarded.

Условие

A vertical insulated cylinder fitted with a frictionless, movable, thermally conducting massless piston contains air at pressure p0=1 atmp_0=1\ \mathrm{atm}, volume Vi=3.0 LV_i=3.0\ \mathrm L, and temperature T0=300 KT_0=300\ \mathrm K. Assume the gas is ideal with a ratio of specific heats γ=1.4\gamma=1.4. The system is initially in equilibrium with its surroundings at temperature T0T_0 and pressure p0p_0. The piston is then moved so that the gas is compressed to a final volume Vf=2.0 LV_f=2.0\ \mathrm L.

Native thermally conducting massless piston in insulated cylinder, whole piston annotation and gas dots.

This compression is performed in three different ways:

(a) The piston is moved slowly, so that the compression remains quasistatic and the gas stays in thermal equilibrium with the surroundings throughout (isothermal process). Calculate the total heat exchanged QaQ_a in the process. [3 т.]

(b) The piston is moved quickly but smoothly, so that during compression heat exchange with the surroundings is negligible (adiabatic and reversible). After compression, the gas is allowed to exchange heat with the surroundings without any change in volume, and it returns to the equilibrium temperature T0T_0. Calculate the total heat exchanged QbQ_b in the process. [3 т.]

(c) The piston is moved suddenly, producing a rapid, irreversible adiabatic compression. After compression, the gas reached a temperature TcT_c. The gas is now left to exchange heat with the surroundings without further change in the volume, and eventually returns to its equilibrium temperature T0T_0. Calculate TcT_c and the total heat exchanged QcQ_c in the process. [5 т.]

Отговори

Решение

Теми и трудност

Оценена трудност: 3/5.

Топлинни явления · Идеални газове · Първи принцип на термодинамиката · Топлообмен

Предпоставки: Гимназиална подготовка, Разширена олимпиадна подготовка


Оригинал в Архива: INPhO2026-Question.pdf · официални решения: INPhO2026-Solution.pdf