IOAA 2018, Теория — Задача 6. Observe the Sun with FAST
Theoretical Competition · 25 т.
Указания
- The theoretical competition will be 5 hours in duration and is marked out of a total of 300 points.
- There are Answer Sheets for carrying out detailed work/rough work. On each Answer Sheet, please fill in
- Student Code
- Question No.
- Page no. and total number of pages.
- Start each problem on a separate Answer Sheet. Please write only on the printed side of the sheet. Do not use the reverse side. If you have written something on any sheet which you do not want to be marked, cross it out.
- Please remember that the graders may not understand your language. As far as possible, write your solutions only using mathematical expressions and numbers. If it is necessary to explain something in words, please use short phrases (if possible in English).
- You are not allowed to leave your working desk without permission. If you need any assistance (malfunctioning calculator, need to visit a restroom, need more Answer Sheets, etc.), please put up your hand to signal the proctor.
- The beginning and end of the competition will be indicated by a long sound signal. Additionally, there will be a short sound signal fifteen minutes before the end of the competition (before the final long sound signal).
- At the end of the competition you must stop writing immediately. Sort and put your sheets in separate stacks,
- (a) Stack 1: answer sheets of part 1
- (b) Stack 2: answer sheets of part 2
- (c) Stack 3: answer sheets of part 3
- (d) Stack 4: question papers and paper sheets that you do not want to be graded.
- Wait at your table until your envelope is collected. Once all envelopes are collected, your student guide will escort you out of the competition room.
- A list of constants for this competition is given on the next page.
Point distribution of this exam
| Problem number | Points |
|---|---|
| T1 | 10 |
| T2 | 10 |
| T3 | 10 |
| T4 | 10 |
| T5 | 10 |
| T6 | 25 |
| T7 | 25 |
| T8 | 25 |
| T9 | 25 |
| T10 | 75 |
| T11 | 75 |
| Total | 300 |
Table of constants
| Mass () | kg | Earth |
| Radius () | m | |
| Acceleration of gravity () | 9.81 ms | |
| Obliquity of Ecliptic | 23°27′ | |
| Length of Tropical Year | 365.2422 mean solar days | |
| Length of Sidereal Year | 365.2564 mean solar days | |
| Albedo | 0.39 | |
| Mass (☾) | kg | Moon |
| Radius (☾) | m | |
| Mean Earth-Moon distance | m | |
| Orbital inclination with the Ecliptic | 5.14° | |
| Albedo | 0.14 | |
| Apparent magnitude (mean full moon) | −12.74 | |
| Mass () | kg | Sun |
| Radius () | m | |
| Luminosity () | W | |
| Absolute Magnitude | 4.80 mag | |
| Surface Temperature | 5772 K | |
| Angular diameter at Earth | 30′ | |
| Orbital velocity in Galaxy | 220 kms | |
| Distance from Galactic center | 8.5 kpc | |
| 1 au | m | Physical constants |
| 1 pc | 206265 au | |
| Gravitational constant () | Nmkg | |
| Planck constant () | Js | |
| Boltzmann constant () | JK | |
| Stefan-Boltzmann constant () | WmK | |
| Hubble constant () | 67.8 kmsMpc | |
| Speed of light in vacuum () | 299792458 ms | |
| Magnetic Permeability of free space () | Hm | |
| 1 Jansky (Jy) | W mHz |
Rayleigh-Jeans law is given by , which is the power emitted per unit emitting area, per steradian, per unit frequency.
Условие
The Five-hundred-meter Aperture Spherical radio Telescope (FAST) is a single-dish radio telescope located in Guizhou Province, China. The physical diameter of the dish is 500 m, but during observations, the effective diameter of the collecting area is 300 m.
Consider observations of the thermal radio emission from the photosphere of the Sun at 3.0 GHz with this telescope and a receiver with bandwidth 0.3 GHz.
(a) Calculate the total energy (E) that the receiver will collect during 1 hour of observation.
(b) Estimate the energy needed to turn over one page of your answer sheet (E′). Hint: the typical surface density of paper is 80 gm.
(c) Which one is larger?
Отговори
- (a) 0.000085 J
- (b) 0.005 J
- (c) E′ > E⊙
Решение
Rayleigh-Jeans law to calculate the thermal emission from the sun at 3 GHz states,
which is the power emitted per unit emitting area, per steradian, per unit frequency. Therefore, the solar luminosity at 3 GHz should be:
(3 points)
At the distance of the earth (1 AU), the monochromatic flux from the sun at 3 GHz should be:
Hence the energy flux that FAST will receive is:
(8 points)
And the total energy that the receiver will collect during 1 hour of observation is:
(8 points)
Then we can calculate the work we need to turn over one piece of the answer sheet (A4 paper). The mass of an A4 paper (297mm×210mm) is:
(2 point)
Therefore, the energy of turning it over should be around:
(3 points)
As a consequence, . (1 point)
Оригинал в Архива: Theory Problems.pdf · официални решения: Theory Solutions.pdf