IOAA 2023, Теория — Задача 4. Europa
IOAA 2023 — Theoretical competition · 10 т.
Указания
- Do not touch envelopes until the start of the examination.
- The theoretical examination lasts for 5 hours and is worth a total of 250 marks.
- There are Answer Sheets for carrying out detailed work and Working Sheets for rough work, which are already marked with your student code and question number.
- Use only the answer sheets for a particular question for your answer. Please write only on the printed side of the sheet. Do not use the reverse side. If you have written something on any sheet which you do not want to be evaluated, cross it out.
- Use as many mathematical expressions as you think may help the evaluator to better understand your solutions. The evaluator may not understand your language. If it is necessary to explain something in words, please use short phrases (if possible in English).
- You are not allowed to leave your work desk without permission. If you need any assistance (malfunctioning calculator, need to visit a restroom, etc.), please draw the attention of the supervisor.
- The beginning and end of the examination will be indicated by the supervisor. The remaining time will be displayed on a clock.
- At the end of the examination you must stop writing immediately. Put everything back in the envelope and leave it on the table.
- Once all envelopes are collected, your student guide will escort you out of the examination room.
- A list of constants and useful relations are included in the envelope.
Table of Constants
Fundamental constants
| Constant | Symbol | Value |
|---|---|---|
| Speed of light in vacuum | ||
| Planck constant | ||
| Boltzmann constant | ||
| Stefan-Boltzmann constant | ||
| Elementary charge | ||
| Universal gravitational constant | ||
| Universal electric constant | ||
| Universal gas constant | ||
| Avogadro constant | ||
| Wien’s displacement constant | ||
| Mass of electron | ||
| Mass of proton | ||
| Mass of neutron | ||
| Mass of Helium nucleus | ||
| Atomic mass unit (a.m.u., Dalton) |
Astronomical data
| Data | Symbol | Value |
|---|---|---|
| Hubble constant | ||
| North Ecliptic Pole () | ||
| North Galactic Pole () | ||
| 1 jansky | ||
| 1 parsec | ||
| 1 astronomical unit (au) | ||
| 1 sidereal day | ||
| 1 tropical year | solar days | |
| 1 sidereal year | solar days |
Approximations and Gauss’s formulae
Approximations
Gauss’s formulae
Spherical law of cosines:
Spherical law of sines: .
The Sun, Earth and Moon
The Sun
| Data | Symbol | Value |
|---|---|---|
| Solar luminosity | ||
| Apparent angular diameter of Sun | ||
| Effective temperature of Sun | ||
| Apparent visual magnitude | ||
| Absolute visual magnitude | ||
| Apparent bolometric magnitude | ||
| Absolute bolometric magnitude | ||
| Distance of the Sun from the Galactic centre |
The Earth and Moon
| Data | Symbol | Value |
|---|---|---|
| Obliquity of the ecliptic (Earth) | ||
| Platonic year (period of precession of Earth’s axis) | years | |
| Apparent visual magnitude of full Moon | ||
| Apparent angular diameter of Moon | ||
| Inclination of the lunar orbit to the ecliptic | ||
| Inclination of the lunar equator to its orbital plane | ||
| Lunar sidereal month | ||
| Synodic month | ||
| Tropical month | ||
| Anomalistic month (the average time between two successive Moon’s perigees) | ||
| Draconic month (time between two successive transits of the Moon through the same node) |
The Solar System
| Object | Mean radius [km] | Mass [kg] | Semimajor axis [au] | Eccentricity |
|---|---|---|---|---|
| Sun | — | — | ||
| Mercury | ||||
| Venus | ||||
| Earth | ||||
| Moon | (range –) | |||
| Mars | ||||
| Jupiter | ||||
| Saturn | ||||
| Uranus | ||||
| Neptune |
General Marking Scheme
| Case | Marking |
|---|---|
| Using incorrect physical concept (despite correct answers) | No points given |
| Giving correct answer without detailed calculation | Deduct 50% of the marks for that part |
| Minor mistakes in the calculations, e.g., wrong signs, symbols, substitutions | Deduct 20% of the marks for that part |
| Units missing from final answers | Deduct 0.5 pts |
| Too few or too many significant figures in the final answer | Deduct 0.5 pts |
| Error resulting from another error in an earlier part for which the student already lost marks, if the answer is physically reasonable. | Full points (i.e., no deductions) |
| Error resulting from another error in an earlier part, where the student should have realised the answer was physically unreasonable. | Deduct 20% of the marks for that part |
For example, if due to an error in an earlier part, the student calculates the mass of a star as instead of , they will only lose marks for the earlier part. However, if, for the same reason, a student calculates the mass as , they should realize this is wrong (a few times the Earth’s mass) and thus should lose some marks for this part as well.
Условие
a. Assuming that the ice covering the ocean on Europa is thick, that the surface temperature on the night side of Europa is and that the temperature at the ice-water boundary is , calculate the total power corresponding to the heat emitted from the interior of this moon.
b. On Earth, the mean geothermal heat flux measured at the continental surface is and originates mainly from radioactive decay. Is the heat emanating from the interior of Europa more likely to come from radioactive decay or tidal forces? Assume that Earth and Europa have a similar isotopic composition. (Select the correct answer on the answer sheet and show your working.)
Notes: the heat passing through a wall with a surface area and thickness in time is described by the formula:
where stands for thermal conductivity and for the temperature difference.
The thermal conductivity of ice . The mass and radius of Europa are and .
Решение
(a) From the formula , calculate the power of the heat flowing through a unit of the surface of ice:
(1 point)
Approximating the ice crust of Europa as a ‘wall’, i.e. that the upper and lower surfaces are of equal area , we obtain the power per unit surface area: (1 point)
Substituting the data we obtain
(1 point)
similar to the value given for the Earth.
The total power emitted inside Europa is therefore equal to
(2 points)
(b) The total power emitted inside the Earth is equal to
(1 point)
which is about larger than the value for Europa. However, the mass ratio is 124. For the heat in Europa’s interior to have a purely radioactive origin, the matter on Europa would have to contain an order of magnitude more radioactive elements per unit mass, which excludes this explanation. (3 points)
Thus the answer must be tidal forces. (1 point)
Original PDF comments
The original solution PDF contains two comments attributed to IOAA on this page:
“In previuos erratic version it was "... - 1".”
“In previous erratic version it was L_2/L_1 = ...”
Бележки за изданието
The English question packet includes a Ukrainian answer form for problem 9. The constants table prints Earth’s obliquity as 23.5′ and the Moon’s semimajor axis in km under an au heading. In the eclipse key, the magnitude addition and luminosity-ratio labels differ from its derivation and results; the original PDF correction comments are retained. Aldebaran’s key prints 4412 km/h and then uses 4416 in the angular-speed numerator. The X-ray question and key allocate points to parts (c) and (d) differently. DART’s alternative calculation prints both 0.17622 and 0.17662 m/s. The LISA key labels the component-mass calculation Part (b), repeats one algebra line and prints the period factor with a positive square. These printed discrepancies remain literal.
Оригинал в Архива: theory.pdf · официални решения: th_solutions.pdf