IOAA 2025, Анализ на данни — Задача 2. D02 · Predicting arrival times of coronal mass ejections on Earth

18th IOAA, Mumbai 2025 — Data Analysis Examination · 60 т.

Внимание: Бележка към темата

The obtained Summary Answersheet contains D02 only. Referenced D01 response forms were unavailable; all D01 data graphs printed in the question and solution booklets are retained.

Условие

The Sun occasionally releases magnetized plasma, termed coronal mass ejections (CMEs), that originate from the surface of the Sun and propagate outwards. Accurate prediction of their arrival times at Earth is crucial for understanding and mitigating their potential effects on satellites orbiting the Earth. In this problem, we aim to predict the arrival times of CMEs by developing an empirical model, using the data of 10 CMEs. Throughout this problem, the distance between the Sun’s surface and Earth is taken to be 214 R⊙214\,R_\odot. Further, assume that the Sun is not rotating.

Due to electromagnetic, gravitational and drag forces, CMEs experience a variable acceleration throughout their propagation. In the first two parts of this problem, we assume that the region between the Sun and the Earth is vacuum.

CMEs through vacuum

(D02.1) The initial velocity, uu, at the solar surface (=1 R⊙)(=1\,R_\odot), the final velocity, vv, upon reaching Earth, and the time to arrive at Earth after leaving the surface of the Sun (in hours), τ\tau, are given for 10 CMEs in the following table.

CME Nameuu (km s−1\mathrm{km\ s^{-1}})vv (km s−1\mathrm{km\ s^{-1}})τ\tau (h\mathrm h)
CME-A80447074.5
CME-B247360127.5
CME-C523396103.5
CME-D83041571.0
CME-E665400104.5
CME-F347350101.5
CME-G44637599.5
CME-H15536097.0
CME-I101651567.0
CME-J68341054.0

(D02.1a) [3 marks] Calculate the average acceleration, aa, for each CME in m s−2\mathrm{m\ s^{-2}}.

(D02.1b) [15 marks] We assume an empirical model for the acceleration, amodela_{\mathrm{model}}, of a CME, which depends on its initial velocity, uu, as amodel=m(uu0)+αa_{\mathrm{model}}=m\left(\frac u{u_0}\right)+\alpha where, amodela_{\mathrm{model}} is expressed in m s−2\mathrm{m\ s^{-2}}, uu is expressed in km s−1\mathrm{km\ s^{-1}} and u0=1.00×103 km s−1u_0=1.00\times10^3\ \mathrm{km\ s^{-1}}.

Determine the constants mm and α\alpha and their associated uncertainties using an appropriate graph (mark your graph as “D02.1b”).

(D02.1c) [4 marks] For each CME, tabulate amodela_{\mathrm{model}} in m s−2\mathrm{m\ s^{-2}}. Hence calculate the root-mean-square (rms) deviation of acceleration, δarms\delta a_{\mathrm{rms}}, between the calculated accelerations, aa, and the model values, amodela_{\mathrm{model}}.

(D02.2) We consider two other CMEs: CME-1 and CME-2, with initial velocities, u=1044 km s−1u=1044\ \mathrm{km\ s^{-1}} and 273 km s−1273\ \mathrm{km\ s^{-1}}, respectively.

(D02.2a) [4 marks] Using the empirical model obtained in (D02.1b), calculate the predicted arrival times at Earth, τ1,m\tau_{1,m} and τ2,m\tau_{2,m} (in hours), for CME-1 and CME-2, respectively.

(D02.2b) [2 marks] The observed arrival times at Earth of CME-1 and CME-2 are 46.0 h46.0\ \mathrm h and 74.5 h74.5\ \mathrm h, respectively. The empirical model is considered to be VALID for a particular CME if its predicted arrival time is within 20% of its observed arrival time; otherwise, it is NOT VALID. Indicate the validity of the model for each CME by ticking (✓) the appropriate box in the Summary Answersheet.

CMEs in presence of solar wind

In reality, the space between the Sun and the Earth is permeated with the solar wind, which exerts a drag force on CMEs. This drag force can either decelerate or accelerate a CME, depending on the CME’s velocity relative to that of the solar wind. To account for the solar wind’s influence, we will use a “drag-only” model for distances Robs(t)≥R0R_{\mathrm{obs}}(t)\ge R_0, where R0R_0 is the distance beyond which the drag force becomes the dominant force affecting the CME’s motion.

The distance from the surface of the Sun as determined from the “drag-only” model, RD(t)R_D(t), and velocity, VD(t)V_D(t), of a CME in this model is given by

RD(t)=Sγln⁡[1+Sγ(V0−Vs)(t−t0)]+Vs(t−t0)+R0R_D(t)=\frac S\gamma\ln[1+S\gamma(V_0-V_s)(t-t_0)]+V_s(t-t_0)+R_0
VD(t)=V0−Vs1+Sγ(V0−Vs)(t−t0)+VsV_D(t)=\frac{V_0-V_s}{1+S\gamma(V_0-V_s)(t-t_0)}+V_s

where, γ=2×10−8 km−1\gamma=2\times10^{-8}\ \mathrm{km^{-1}}, VsV_s is the constant speed of the solar wind, R0R_0 and V0V_0 are the distance and velocity, respectively, at time t0t_0, and SS is the sign factor. S=1S=1 if V0>VsV_0>V_s; S=−1S=-1 if V0≤VsV_0\le V_s.

(D02.3) The tables below show the observed radial distance from the surface of the Sun, Robs(t)R_{\mathrm{obs}}(t) (measured in R⊙R_\odot), as a function of time, tt (in hours), for two CMEs: CME-3 and CME-4. The last data point in each table (D5 and P8, respectively) corresponds to the arrival time of the respective CME at Earth. For this part, assume Vs=330 km s−1V_s=330\ \mathrm{km\ s^{-1}}.

CME-3

Data pointtt (in h)Robs(t)R_{\mathrm{obs}}(t) (in R⊙R_\odot)
D10.2006.36
D20.4807.99
D31.2211.99
D41.4913.51
D558.05214

CME-4

Data pointtt (in h)Robs(t)R_{\mathrm{obs}}(t) (in R⊙R_\odot)
P11.004.00
P23.006.00
P34.009.00
P45.0011.0
P521.043.0
P650.0100
P785.0170
P8111214

We shall evaluate if the “drag-only” model satisfactorily predicts the arrival times of these CMEs. To use this model an appropriate choice of t0t_0, and corresponding R0R_0 and V0V_0 needs to be made.

(D02.3a) [6 marks] For CME-3, take the following two cases:

(C1) t0t_0 is taken as the midpoint of the interval D1 – D2

(C2) t0t_0 is taken as the midpoint of the interval D3 – D4

Assume the velocity remains constant in each specific interval D1–D2 and D3–D4, but may differ between the two intervals.

Using t0t_0, R0R_0, and V0V_0, calculate the difference between the observed and the predicted radial distance, δRD≡Robs(t)−RD(t)\delta R_D\equiv R_{\mathrm{obs}}(t)-R_D(t) in units of R⊙R_\odot at t=58.05 ht=58.05\ \mathrm h, for each of the two cases.

(D02.3b) [4 marks] Evaluate RD(t)R_D(t) at points, P5, P6, P7, and P8 between the Sun and the Earth for CME-4 for the following two cases adopting the procedure similar to (D02.3a):

(C3) t0t_0 is taken as the midpoint of the interval P1 – P2

(C4) t0t_0 is taken as the midpoint of the interval P3 – P4

(D02.3c) [10 marks] Plot RD(t)R_D(t) (in R⊙R_\odot) vs tt (in hours) for the two cases, C3 and C4, for CME-4 at points, P5, P6, P7, and P8 (mark your graph as “D02.3c”). On the same graph, draw smooth curves of RD(t)R_D(t) for the above mentioned two cases. For this part, take the range of xx axis from 0 to 180 h.

(D02.3d) [4 marks] Using the graph, estimate the absolute difference, ∣δτ∣|\delta\tau| between the actual arrival time of CME-4 at the Earth and its time of arrival predicted by the drag-only model, for each of the cases C3 and C4.

(D02.3e) [1 mark] Indicate whether the following statement is TRUE or FALSE by ticking (✓) the appropriate box in the Summary Answersheet (no written justification needed):

“The drag forces exerted by the solar wind on CMEs become dominant for CME-3 at an earlier time compared to CME-4.”

(D02.4) [7 marks] Consider drag as the dominant force acting on 10 CMEs in part D02.1. Assume that the “drag-only” model is applicable from the surface of the Sun (R0=1 R⊙)(R_0=1\,R_\odot) and beyond, for all CMEs. Estimate and tabulate the solar wind speed VsV_s in km s−1\mathrm{km\ s^{-1}} for each CME. Further, estimate the average solar wind speed Vs,avgV_{s,\mathrm{avg}} for all 10 CMEs.

Решение

D02 Summary Answersheet — SA-1

Summary Answersheet — FRONT

Contestant Code: ______ – ______

Q. No. D02 · Page No. SA-1

Final answers

(D02.1a) Marks (3.0)

CME Nameuu (km s−1\mathrm{km\,s^{-1}})vv (km s−1\mathrm{km\,s^{-1}})τ\tau (h)
CME-A80447074.5
CME-B247360127.5
CME-C523396103.5
CME-D83041571.0
CME-E665400104.5
CME-F347350101.5
CME-G44637599.5
CME-H15536097.0
CME-I101651567.0
CME-J68341054.0

(D02.1b) Marks (15.0)

Graph number: D02.1b

m=m= ______

α=\alpha= ______

D02 Summary Answersheet — SA-2

Summary Answersheet — BACK

Contestant Code: ______ – ______

Q. No. D02 · Page No. SA-2

Final answers

(D02.1c) Marks (4.0)

CME Nameamodela_{\mathrm{model}} (m s−2\mathrm{m\,s^{-2}})
CME-A
CME-B
CME-C
CME-D
CME-E
CME-F
CME-G
CME-H
CME-I
CME-J

δarms=\delta a_{\mathrm{rms}}= ______

(D02.2a) Marks (4.0)

τ1,m=\tau_{1,\mathrm m}= ______ h

τ2,m=\tau_{2,\mathrm m}= ______ h

(D02.2b) Marks (2.0)

VALIDNOT VALID
CME-1
CME-2
D02 Summary Answersheet — SA-3

Summary Answersheet — FRONT

Contestant Code: ______ – ______

Q. No. D02 · Page No. SA-3

Final answers

(D02.3a) Marks (6.0)

C1:

δRD=\delta R_D= ______ R⊙R_\odot

C2:

δRD=\delta R_D= ______ R⊙R_\odot

(D02.3b) Marks (4.0)

Data Pointtt (h)C3: RD(t)R_D(t) (R⊙R_\odot)C4: RD(t)R_D(t) (R⊙R_\odot)
P521.0
P650.0
P785.0
P8111

(D02.3c) Marks (10.0)

Graph number: D02.3c

D02 Summary Answersheet — SA-4

Summary Answersheet — BACK

Contestant Code: ______ – ______

Q. No. D02 · Page No. SA-4

Final answers

(D02.3d) Marks (4.0)

C3: ∣δτ∣=|\delta\tau|= ______

C4: ∣δτ∣=|\delta\tau|= ______

(D02.3e) Marks (1.0)

TRUE □  FALSE □

(D02.4) Marks (7.0)

CME Nameuu (km s−1\mathrm{km\,s^{-1}})vv (km s−1\mathrm{km\,s^{-1}})τ\tau (h)VsV_s (km s−1\mathrm{km\,s^{-1}})
CME-A80447074.5
CME-B247360127.5
CME-C523396103.5
CME-D83041571.0
CME-E665400104.5
CME-F347350101.5
CME-G44637599.5
CME-H15536097.0
CME-I101651567.0
CME-J68341054.0

Vs,avg=V_{s,\mathrm{avg}}= ______

Total: ______

End of Summary Answersheet


Оригинал в Архива: Data-Analysis-Questions.pdf · официални решения: Data-Analysis-Solutions.pdf · допълнителни данни: Data-Analysis-Summary-Answersheet.pdf