IOM 2020, Експеримент — Задача 12

• Q.12 a) KDP 0.5 cm: 0.107 %; KDP 2.0 cm: 1.51943 %; KDP 4.0 cm: 2.787%
• Q.12 b) Yes for all three crystals.
• Q.12 c) $P_{2\omega} \sim P_{\omega}^{2}$
• Q.12 d) B = 1.993 ≈ 2 (0.5 cm), 2.0001 ≈ 2 (2.0 cm), 2.0185 ≈ 2 (4.0 cm)

Answer 12 a)

KDP 0.5 cm 0.107 %, 0,09 - 0,11% - OK

KDP 2.0 cm 1.51943 %, 1,43 - 1,52%- OK

KDP 4.0 cm 2.787%, 2,7 – 2,8%- OK

The main thing is to count at maximum power. $\frac{P_{max}(2\omega)}{P_{max}(\omega)} \cdot 100\%$

Answer 12 b)

KDP 0.5 cm Yes

KDP 2.0 cm Yes

KDP 4.0 cm Yes

For all crystals, conversion efficiency $< 10\%$

Answer 12 c) $P_{2\omega} \sim P_{\omega}^{2}$

$I_{2\omega} \sim I_{\omega}^{2}$

Quadratic dependence

Answer 12 d)

KDP 0.5 cm $A = 10^{-9}\ldots19^{-8}$ $B = 1.993 \approx 2$

KDP 2.0 cm $A = 10^{-8}\ldots19^{-7}$ $B = 2.0001 \approx 2$

KDP 4.0 cm $A = 10^{-7}\ldots19^{-6}$ $B = 2.0185 \approx 2$

Plot dependencies in double logarithmic scale. Draw a line (i.e., reveal the slope) and calculate the degree. All degrees are about 2. Taking into account the inaccuracy of the plots. The values of the coefficients A are not so important. The order of magnitude is important. See Additional Forms 1.

Additional forms 1

For crystal 0.5 см, B = 1.993 ≈ 2

For crystal 2 см, B = 2.0001 ≈ 2

Additional forms 2

For crystal 4 см, B = 2.0185 ≈ 2