IOM 2021, Блиц — Задача 37

The Blitz-contest of IOM-2021

Условие

A block of mass mm is launched horizontally onto a curved wedge of mass MM at a velocity vv. What is the maximum height reached by the block after it shoots off the vertical segment of the wedge? Assume all surfaces are frictionless; both the block and the curved wedge are free to move.

A small block m moving with velocity v (arrow to the right) on a horizontal base towards a wedge M whose surface curves up from the base into a vertical segment.
  • v22g\frac{v^2}{2g}
  • (mm+M)2v22g\left(\frac{m}{m+M}\right)^2 \frac{v^2}{2g}
  • (Mm+M)2v22g\left(\frac{M}{m+M}\right)^2 \frac{v^2}{2g}
  • mm+Mv22g\frac{m}{m+M} \frac{v^2}{2g}
  • Mm+Mv22g\frac{M}{m+M} \frac{v^2}{2g}

Отговори

Решение


Оригинал в Архива: iom-2021-blitz-tasks-eng.pdf · официални решения: iom-2021-blitz-answers-eng.pdf