IPhO 2026, Теория — Задача 3. Chasing the absolute zero

Theoretical Exam -- English (Official) · 10 т.

Условие

A refrigeration cycle must be carried out by a system with characteristics appropriate for the temperatures to be achieved. One hundred years ago, in 1926, the chemist William Giauque and, independently, the physicist Peter Debye proposed paramagnetic salts as ideal systems for lowering temperatures far below 1 K. Indeed, beginning in the following decade, temperatures as low as 0.0044 K were achieved (Wander de Haas and Gerrit Wiersma, 1935, Leiden Cryogenic Laboratories). In this question, the paramagnetic Carnot refrigeration cycle is studied.

Consider a torus with mean radius RR and inner radius rr made of a homogeneous, isotropic paramagnetic material, around which an insulated conducting wire is wound, with its ends connected to an external voltage source (emf), as shown in figure 3a. The resistance of the wire is so low that energy losses due to the heating of the wire can be neglected. The winding is dense, with NN turns in total, and it is assumed that r≪Rr \ll R, so that the fields H⃗\vec{H} and B⃗\vec{B} and the magnetization M⃗\vec{M} have approximately constant magnitudes throughout the torus. Let VV and AA be the volume and the cross-section area of the torus. Hereinafter, the abbreviation Pm-T is used to refer to the paramagnetic torus.

A torus densely wound with an insulated conducting wire whose two ends are connected to an external voltage source labelled ℰ (drawn as a battery symbol). Red arrows mark the mean radius R (from the centre of the hole to the middle of the winding) and the tube diameter 2r.
Fig. 3a.

In paramagnetic materials, M⃗\vec{M} is parallel to H⃗\vec{H} and the following relation holds:

B⃗=μ0H⃗+μ0M⃗.\vec{B} = \mu_0 \vec{H} + \mu_0 \vec{M}.

Energy transfer sign convention: in this problem, Work (WW) and Heat (QQ) are considered positive when they flow into the system, and negative when they flow out.

T3-A [1.0 pts]. Work in the Pm-T

Hint: in magnetic materials, ∮CH⃗⋅dℓ⃗=IC\oint_C \vec{H} \cdot d\vec{\ell} = I_C, where ICI_C is the net free current passing through the area bounded by the closed curve CC.

T3-A1 Let HH be the magnitude of H⃗\vec{H} in the torus. Write HH in terms of NN, AA, VV and the instantaneous electric current II in the wire. [0,2 т.]

T3-A2 Let dWemfdW_{emf} be the work that the external voltage source performs to change the magnitude of B⃗\vec{B} by dBdB. Write dWemfdW_{emf} in terms of VV, HH, and dBdB. [0,6 т.]

T3-A3 The total work done by the voltage source, dWemfdW_{emf}, can be divided in two parts: the work that would be performed to change the magnetic field if the toroid had a vacuum core, dWvacdW_{vac}, and the work done on the paramagnetic material itself, dWdW. Write dWdW in terms of μ0\mu_0, HH, VV and dMdM. [0,2 т.]

T3-B [3.0 pts]. Heat and temperature in the Pm-T

The following table compares two thermodynamic systems: the ideal gas and the Pm-T. Use this information and your answer to question T3-A3 to solve the following questions. This information will also be used in part C. If you did not find an answer for dWdW in question T3-A3, you may use dW=αVμ0HdMdW = \alpha V \mu_0 H dM where α\alpha is a number. The volume VV of the paramagnetic torus is constant, so that there is no work due to pressure. Below, TT is the temperature in all instances.

IDEAL GASPARAMAGNETIC TORUS
State functions: P,VP, V and temperature TTState functions: H,MH, M and temperature TT
Constants: R,γR, \gamma and number of moles nnConstants: K,λK, \lambda and number of moles nn
Equation of state: PV=nRTPV = nRTEquation of state: TMV=nKHTMV = nKH
Heat capacity at constant VV: CV=nR/(γ−1)C_V = nR/(\gamma - 1)Heat capacity at constant MM: CM=nλ/T2C_M = n\lambda/T^2
Internal energy UU in any process satisfies dU=CVdTdU = C_V dTInternal energy UU in any process satisfies dU=CMdTdU = C_M dT

KK and λ\lambda are constants given by the material in the torus. You may use the equations provided in the table directly without proving them.

T3-B1 If the magnitude of H⃗\vec{H} changes from HiH_i to HfH_f at a constant temperature TT, an energy QQ is transferred between the Pm-T and its environment. Write QQ in terms of μ0\mu_0, nn, VV, KK, HiH_i, HfH_f, and TT. [1,5 т.]

T3-B2 If the magnitude of H⃗\vec{H} changes adiabatically from HiH_i to HfH_f, the temperature of the Pm-T changes from TiT_i to TfT_f. Write ΔT=Tf−Ti\Delta T = T_f - T_i in terms of μ0\mu_0, VV, nn, KK, λ\lambda, HiH_i, HfH_f, and TiT_i. [1,5 т.]

T3-C [6.0 pts]. Carnot refrigerator of the Pm-T

H vs. T diagram of the Carnot cycle: axes H (vertical) and T (horizontal). Vertices 1 (top right) and 4 (lower right) lie on a vertical line at the higher temperature, vertices 2 and 3 on a vertical line at the lower temperature; curved adiabats join 1 to 2 and 3 to 4. Dashed vertical lines drop from 3 and 4 to the T axis.
Fig.3b.

The HH vs. TT diagram of the Carnot refrigeration cycle 1→2→3→4→11 \to 2 \to 3 \to 4 \to 1 performed by the Pm-T is shown in figure 3b. In this cycle, let:

ThT_h: temperature of the hot reservoir

TcT_c: temperature of the cold reservoir

QhQ_h: absolute value of the heat transferred to the hot reservoir

QcQ_c: absolute value of the heat absorbed from the cold reservoir

T3-C1 Mark ThT_h and TcT_c on the TT axis of the HH vs. TT diagram. Also label the processes in which the transfers of QhQ_h and QcQ_c occur, respectively. [0,2 т.]

T3-C2 Let M1M_1, M2M_2, M3M_3, and M4M_4 be the magnitudes of M⃗\vec{M} at the vertices of this cycle. Write M1M_1 in terms of M2M_2, M3M_3, and M4M_4. [1,5 т.]

T3-C3 Suppose that to cool 1.00 L of liquid helium initially at 1.00 K, we utilize a 2.0 moles Pm-T made of potassium chromate. For this material, K=1.87×10−6K = 1.87 \times 10^{-6} K·m3^3/mol, its density is 27302730 kg/m3^3 and its molar mass is 0.190.19 kg/mol. The Pm-T performs a Carnot refrigeration cycle with H1=411624H_1 = 411624 A/m, H2=311306H_2 = 311306 A/m, H3=204618H_3 = 204618 A/m and H4=240446H_4 = 240446 A/m. After one operating cycle, calculate the final temperature of the liquid helium. Assume that for the liquid helium both the specific heat capacity c=100c = 100 J/(kg·K) and the density ρ=130\rho = 130 kg/m3^3 remain constant. [0,8 т.]

T3-C4 In order to continuously lower the temperature of a body with constant heat capacity CcC_c, Carnot cycles are allowed to occur over time in such a way that the power PP transferred to the refrigerator remains constant. It is then assumed that the temperature ThT_h of the hot reservoir remains constant and that in each operating cycle the temperature TcT_c of the cooled body decreases by dTcdT_c, satisfying the relation dQc/dQh=Tc/ThdQ_c/dQ_h = T_c/T_h. If at t=0t = 0 we have Tc=T0T_c = T_0, determine the time tt that the Carnot refrigerator must operate for the cooled body to reach a temperature T<T0T < T_0. Express your answer in terms of CcC_c, ThT_h, PP, T0T_0 and TT. [2 т.]

T3-C5 The efficiency of a refrigerator is quantified by its coefficient of performance COP=Qc/W\mathrm{COP} = Q_c/W. Determine the overall COP of the refrigerator of question T3-C4 with all the cycles performed until time tt. Write your answer in terms of T0T_0 and ThT_h and TT. [1,5 т.]

Отговори

Решение


Оригинал в Архива: T3.pdf · официални решения: theory_sol.pdf