RMPh 2017, Експеримент, 28 октомври — Задача 1. Experimental Problem

Romanian Master of Physics 2017 — Experimental Exam - October 28, 2017 · 28 октомври 2017 г.

Внимание: Бележка към темата

The official solutions (answer sheet) exist only in Romanian and are reproduced verbatim in Romanian.

Условие

The experimental problem proposes you to study and calibrate a device dedicated to light polarization measurement and to use the calibrated device to determine the unknown concentration of a sugar solution in water.

For this experimental problem, you are not required to calculate errors.

2. Description of experimental setup

On the work table are components and electrical, optical and mechanical devices.

Warning! Care should be taken not to shine the laser beam or its reflection into your eye or to the eye of another person

Warning! Carefully handle the components of the experimental device, so as not to damage them, as these components will not be replaced!

Photograph of the potentiometer with its three wires ending in green and metal pins.
Potentiometer
1Digital multimeterThe appropriate terminals of the multimeter are used to connect the wires. For voltage measurement set the selection knob to 2000 m2000\ m in DC range V=V =. The indication is expressed in mV. When the multimeter is not in use, turn the selection knob on OFF.
2BatteryThe battery provides voltages up to 3V. The red pin is the positive terminal of the battery
3PotentiometerPotentiometer is a 22kΩ variable resistor. The ends of the resistance and the cursor are attached to the three metal terminals(pins) marked with PleftP_{left} , PcenterP_{center} , PrightP_{right} .The potentiometer diagram is shown in the figure.
4Electrical circuitThe electrical circuit is composed of a photodiode, a load resistor and four terminals. Electrical resistance of the resistor is100 Ω. The image below present how to connect to terminals1, 2, 3 and 4.
5Pointer laserA paper clip can lock the laser button in the closed position. When not in use, the laser closes. Using the ring (see 6) and one of the paper clip (see 7), the laser is fastened to the upper end of the holder (see 8). The beam of the laser must fall on the photodiode.
6RingThe ring is used to properly fix the laser on the vertical support.The ring should be fastened as close to the end the light is emitted.
7Paper clips and rubber bandsThe paper clips and the rubber bands serve to adequately fix the laser, polarizer and tank to the vertical holder.
8Plate supporting the vertical holderThe plate is used to support the vertical holder on which the laser, polarizer and cuvette are fixed. The laser assembly (laser,ring, paper clip) should be fastened as high as possible on the vertical holder so that the beam can be easily directed towards the surface of the photodiode. A protractor is fixed on the holder to determine the position of the analyzer(see 12).This position is indicated by the toothpick fixed on the analyzer, which can be turned above the photodiode.
9Small cylindrical tank(cuvette)The tank is a transparent cylindrical tube fixed in a plastic rail. The tank is closed at the bottom with a glass plate with plane parallel faces.
10Syringe and hoseIt is recommended that once fixed, the tank is not moved. Injecting and withdrawing liquids from the cuvette is done using the syringe to which hose is attached.
11Storage beakers for solutionsThere are four storage beakers on the table with the concentrations listed on the labels. On the work table, there is a beaker in which to pour the liquids you no longer use in the experiment.
12The analyzerThe analyzer is a small cylinder, with upper part a piece of polarizing filter film. On the side is attached a toothpick that serves to indicate the angle of rotation. The analyzer is placed above the photodiode. At the beginning of any set of measurements the analyzer needle must points toward the 90-degree angle of the protractor.
13The polarizerThe polarizer is a small cylinder having on its upper side a piece of polarizing filter film. The polarizer is fixed on the vertical holder, immediately under the laser. Before finishing, it is rotated so that it is in the „crossed” position with the analyzer.
14RulerThe ruler is used to determine the length of the liquid column in the cuvette.
15Four electrically conductive wires, used for electrical connectionsThe conductive wires are used to connect the voltmeter to measure the voltage across the photodiode and across the load resistor.

3. Theoretical considerations

3.1 POLARIZATION

In classical optics, the oscillations of electric and magnetic fields in electromagnetic wave occur in directions perpendicular to the propagation direction. It is said that the light is polarized linearly if the oscillation of each of the fields occurs in one direction; the direction of the electric field oscillation is defined as the polarization direction.

Electromagnetic wave: perpendicular oscillating magnetic field (B) and electric field (E) along the direction of propagation; wavelength (λ) marked.

Most naturally occurring light sources emit unpolarized light. Lasers emit polarized light, and laser diodes (of the type used in the laser pointers) emit partially polarized light.

There are polarizing filters-films that select light with a certain direction of polarization. Such a filter transmits only the component of the polarized light along a particular direction and absorbs the perpendicular component on the respective direction.

In Figure 1, the transmission direction of the filters is OyOy for the left filter, and Oy′Oy' for the right filter. From the unpolarized beam that reaches the first polarization filter, called polarizer, only the part that has the electric field parallel to the OyOy axis passes on. From the polarized light beam in the OyOy direction that reaches the second polarizing filter, called the analyzer, only the part with the electric field parallel to the Oy′Oy' axis passes on.

As can be seen from the analysis of the bottom right detail of the image in Figure 1, the electric field vector E⃗\vec{E} of light polarized due to polarizer, can be resolved into two perpendicular components Ex′=E⋅sin⁡θE_{x'} = E \cdot \sin\theta and Ey′=E⋅cos⁡θE_{y'} = E \cdot \cos\theta. The Ey′E_{y'} component can pass through the analyzer, while Ex′E_{x'} component is completely blocked.

Unpolarized light passes through a polarizer (transmission direction y) and becomes light polarized on Oy (vertical E arrows), then through an analyzer whose transmission direction y′ makes angle θ with y, to a photodetector along z. Bottom detail: E resolved into E_y′ along y′ and E_x′ along x′; labels 'Unpolarized light', 'Light polarized on Oy direction', 'Light polarized on Oy′ direction'.
Figure 1

Intensity of light II is proportional to the square of the amplitude of the electric field, I∼E2I \sim E^2. Assume that the angle between the polarizer and the analyzer transmission directions is θ\theta. If I0I_0 is the intensity of light in the space between the two polarization filters, then I(θ)I(\theta) the intensity of the light passing beyond the analyzer will depend on the angle θ\theta, according to the relationship

I(θ)=I0⋅cos⁡2θ(1)I(\theta) = I_0 \cdot \cos^2\theta \qquad (1)

This dependence of the intensity of light transmitted through the polarizer – analyzer system is known as Malus’s law. According to this law, under ideal conditions, light does not reach the photodetector, if the polarizer and analyzer are crossed (they have perpendicular transmission axes). When the transmission axes of the polarizing filters are parallel, the signal of the photodetector is maximum.

3.2 Optical activity

For a linearly polarized light beam, the plane containing the propagation direction and polarization direction is called the polarization plane.

The optical activity is represented by the rotation of polarization plane of a linearly polarized light beam when passing through certain materials. The situation is shown in the image in figure 2. The phenomenon occurs only in materials called chiral which, at the microscopic level, lack the reflection symmetry.

Linearly polarized light (vector E) passes through an optically active cylinder of length d; the plane of polarization of the emerging light is rotated by the angle β.
Figure 2

Optical activity can also be seen in solution containing chiral molecules, such as sugars. The rotation of the polarization plane can be either clockwise, right (dextrorotatory compounds) or left (for levorotatory compounds) depending on the stereoisomer that is present or dominant in the medium traversed by the polarized light beam.

For a given substance, the angle β\beta of rotation of the polarization plane is proportional to the length dd of the path through the material and, for a solution, proportional to its concentration cc:

β∼d⋅c(2)\beta \sim d \cdot c \qquad (2)

3.3 Photodiode

In the proposed experiment, a photodiode is used to detect light intensity; this is a diode that allows the conversion of light energy into electrical energy. Characteristic of any diode is its non-ohmic behavior.

Diode I–U characteristic: current I versus voltage U, nearly zero for 'Revers polarization' and rising steeply for 'Direct polarization'.
Figure 3

The relationship between the intensity of the electric current II flowing through a diode and the potential difference UU applied to it has the expression:

I=I0⋅(eq⋅Uη⋅kB⋅T−1)(3)I = I_0 \cdot \left( e^{\frac{q \cdot U}{\eta \cdot k_B \cdot T}} - 1 \right) \qquad (3)

where q=1.60×10−19 Cq = 1.60 \times 10^{-19}\ \mathrm{C} is absolute value of elementary charge, and kB=1.38×10−23 J⋅K−1k_B = 1.38 \times 10^{-23}\ \mathrm{J \cdot K^{-1}} is Boltzmann constant. For experiments under normal conditions, T=300 KT = 300\ \mathrm{K} and q/(kBT)=38.64 V−1q/(k_B T) = 38.64\ \mathrm{V^{-1}}. The parameters that determine the nonlinear response to potential difference U, are diode factor η\eta and saturation current I0I_0. The specific values of these parameters are: I0≅100 nAI_0 \cong 100\ \mathrm{nA} and η≥0,5\eta \ge 0{,}5 .

I–U characteristic of an illuminated photodiode, shifted down; marked U_CD on the U axis, I_SC on the I axis and the region where P is negative.
Figure 4

Current versus voltage I−UI - U characteristics is shown in figure 4 and describe the diode feature as one-way” current valve”, which allows the electric current to pass when diode is direct polarized and blocks the current for reverse polarization. For different values of voltage, the diode has different resistance values. At high direct polarization, the diode resistance is zero. At high reverse polarization, the diode resistance became infinity.

A photodiode on which light falls is equivalent to a diode to which a current generator ILI_L is connected in parallel; the intensity of current ILI_L is proportional to the light flux falling on the active surface of the photodiode.

In this situation, the expression of I−UI - U characteristic of photodiode becomes:

I=I0⋅(eq⋅Uη⋅kB⋅T−1)−IL(4)I = I_0 \cdot \left( e^{\frac{q \cdot U}{\eta \cdot k_B \cdot T}} - 1 \right) - I_L \qquad (4)

Graphical representation of this characteristic is shown in figure 4. As you can see, the graph is "lowered" and penetrates the forth trigonometrical quadrant. Appears a value range I-U where the currents are negative for positive voltages, which determines negative power values - a characteristic specific to the electric generators. Negative (debited) powers are different for different points of the I-U characteristic. The voltage value UCDU_{CD} for current cancellation is called open circuit voltage, and the value of the zero-voltage electrical current ISCI_{SC} is called the short-circuit current.

Equivalent scheme of the photoelement: current generator I_L in parallel with the diode (current I_dioda) and variable load resistor R (current I_R).
Figure 5
I–U characteristic in photoelement mode: curve from I_SC on the I axis down to U_CD on the U axis.
Figure 6

The ratio of the maximum photodiode power to the product ISC⋅UCDI_{SC} \cdot U_{CD} is called the fill factor FFFFFF .
A characteristic I-U of the illuminated photodiode, in the absence of external polarization, can be measured. In such a situation, the diode is said to operate as a photoelement. Its equivalent scheme is - in this case - that shown in Figure 5.
The characteristic points are obtained by varying the load resistance R.
The I-U characteristic obtained, of the type in Figure 6, is actually the part of the fourth quadrant of the photodiode characteristic - for which the axis of the current has the sense inversed.

4. Tasks

Respond to the requirements of the experimental question, by properly completing the boxes in the Answer Sheet.

Please note your student code on the first page of the Answer Sheet.

Photograph of the digital multimeter (orange case, rotary selection knob, display and input sockets).
Digital multimeter
Photograph of the battery holder with two batteries and red and black connection wires.
Battery
Diagram of the potentiometer: a resistor inside a circle with a cursor arrow; three pins labelled P_left, P_center and P_right.
Potentiometer diagram
Photograph of the board with the electrical circuit, the photodiode and four coloured terminals.
Electrical circuit
Connection diagram: terminal 1, photodiode (– and + marked), terminal 2, wire to terminal 3, resistance, terminal 4; labels 'Photodiode' and 'Resistance'.
Terminals 1, 2, 3 and 4
Photograph of the pointer laser with red labels 'Pointer laser' and 'Inel de blocare' (at the locking clip of the button).
Pointer laser
Photograph of the ring fixed on the laser pointer.
Ring
Photograph of three black paper clips and several coloured rubber bands.
Paper clips and rubber bands
Photograph of the vertical holder on its plate with labels: laser, paper clip, polarizer, tank, analyzer, photodiode, protractor.
Plate supporting the vertical holder
Photograph of the small cylindrical tank (cuvette) on a plastic rail, marked with a red arrow 'CUVA'.
Small cylindrical tank (cuvette)
Photograph of the syringe with the attached transparent hose.
Syringe and hose
Photograph of the analyzer: a small cylinder with a dark polarizing film on top and a toothpick attached as a pointer.
The analyzer
Photograph of the polarizer: a small cylinder with a dark polarizing film on top.
The polarizer
Photograph of the coiled conductive wires with green connectors.
Four electrically conductive wires

4.1 Characterization of the photodiode

4.1.1 Measurement of open circuit voltage and short-circuit current

The photodiode is connected to the terminals marked1 (negative terminal) and 2 (its positive terminal). The electrical connections of the photodiode are shown in the diagram in figure 7.

Between the terminals 3 and 4 a resistance R=100 ΩR = 100\ \Omega is connected. If the positive photodiode terminal is connected to the positive terminal of the battery and its negative terminal at the negative terminal of the battery, the diode is said to be forward biased (the direct polarization). Install the laser pointer at the top end of the vertical holder. Start the laser and adjust its position so that the upper surface of the photodiode is uniformly illuminated.
Use the measurement device provided (function selector in positions V=;2000 mV =; 2000\ m and A=;200 mA =; 200\ m )

Connection diagram: terminal 1, photodiode (– and +), terminal 2, terminal 3, resistance, terminal 4.
Figure 7
Potentiometer with pins P_left, P_center, P_right; P_left is wired to terminal 1 (photodiode side) and P_center to terminal 4 (resistance side) of the board: 1 – photodiode – 2 – 3 – resistance – 4.
Figure 8
Battery box (–Black, +Red) connected to pins P_left and P_right of the potentiometer; pin P_center is the cursor.
Figure 9
Battery box (–Black, +Red) connected across P_left and P_right of the potentiometer; P_left wired to terminal 1 and P_center to terminal 4 of the board with photodiode (terminals 1, 2) and resistance (terminals 3, 4).
Figure 10

4.1.1.a. Measure the values of the open circuit voltage UCDU_{CD} and the short-circuit current ISCI_{SC} and write measured values in the appropriate box in the Answer Sheet. [0,5 т.]

Pay attention! Next, you will use the multimeter only to measure voltages.

You will determine the value of the current that passes through the diode by measuring the voltage determined by this current on the resistor R=100 ΩR = 100\ \Omega, connected in series with the photodiode.

4.1.2 Measurement of the characteristic I−UI - U in the fourth trigonometric quadrant (in photoelement mode)

Connect the pins pleftp_{left} and pcenterp_{center} of the potentiometer to the terminals 1 and 4 of the measuring device. The circuit diagram is shown in figure 8. Rotating the potentiometer knob, vary the resistance of the photodiode circuit.
Turn on the pointer laser and illuminate the surface of the photodiode. Always keep in mind that during the measurements, the illumination of the photodiode will not change. Vary the potentiometer resistance (rotating the knob). For each position of the potentiometer, measure the voltage drops on the photodiode and on the load resistance.

4.1.2.a. Fill in Table 1 of the Answer Sheet with pairs of current-voltage - measured data. [2 т.]

4.1.2.b. Draw the I−UI - U graph of the data recorded, including those obtained in the task4.1.1. a. Name the graph you plotted Graph 1. [1 т.]

4.1.2.c. Draw the graph of the power output by the diode (as generator) as function of the current through the photodiode. Name the graph you plotted Graph 2. [1 т.]

4.1.2.d. Determine the value of the fulfill factor FFF for the photodiode provided. [0,5 т.]

4.1.3. Measurement of the characteristic I−UI - U in the first trigonometric quadrant

By using the provided voltage source and the potentiometer set up the electrical circuit according to the electrical diagram in Figure 9. The circuit thus constructed provides polarization with variable voltages for the photodiode, playing the role of a variable voltage source. Connect the negative pole of the source to the left contact of the potentiometer. Connect the variable source to the circuit on the board so that the diode is polarized directly (Figure 10). The left pin of the potentiometer connects to terminal 1, and the center pin - the cursor - to terminal 4.

4.1.3.a. With the laser turned off, measures pairs of I-U values for currents I≤20 mAI \le 20\ \mathrm{mA}. Fill in Table 2 from the Answer Sheet with measured pairs current-voltage. [2 т.]

4.1.3.b. Determine a linearized expression of characteristic I=I0⋅(eq⋅Uη⋅kB⋅T−1)I = I_0 \cdot \left( e^{\frac{q \cdot U}{\eta \cdot k_B \cdot T}} - 1 \right), suitable for direct polarization. [0,5 т.]

4.1.3.c. Using the experimental data obtained and the expression deduced in the task 4.1.3.b., determine the value of the parameter η\eta of the photodiode used. [1 т.]

4.1.4 Measuring the characteristic I−UI - U in the third trigonometric quadrant

By inverting the battery connections to the potentiometer, the photodiode becomes reverse polarized.

4.1.4.a. With the laser on and with the illuminated photodiode, measures pairs of values I-U for polarization voltages U≤3VU \le 3V. Fill in Table 3 on The Answer Sheet with the current-voltage pairs measured in this task. [2 т.]

4.1.4.b. Draw the graph of I-U characteristic in the third quadrant, for the illuminated and polarized photodiode. Name the graph you plotted in Graph 3. [1 т.]

4.2 Calibration of the electrical system for measurements on the intensity of light

This part of the problem has the goal to establish a link between the photodiode's electrical signal (reverse polarization current) and the intensity of the light. To vary the light intensity, use the laser assembly, the polarizer, the analyzer, and consider the Malus law, described by relation (1).

Mutual orientation of polarizer and analyzer

Make a primary adjustment of the reciprocal position of the polarizer and analyzer transmission directions. For this, look through the polarizer and analyzer overlapped; rotates the polarizer until the light don’t pass through the area where the polarizing filters overlap. Mark the position on the polarizer next to the indicator needle on the analyzer. The determined position is the approximate position in which the polarizer and the analyzer are crossed. Place the analyzer over the photodiode with the needle in position 90∘90^{\circ} and fix the polarizer crossing with the analyzer.

4.2.1 Measuring the electrical signal of the photodiode

Place the analyzer over the photodiode with the indicator needle at position 90 degrees. Attaches the polarizer to the top of the vertical holder in the cross position with the analyzer - underneath the laser that is also attached to the vertical support. Adjusts the position of the laser so that the surface of the photodiode is fully illuminated.

4.2.1.a. Rotates the analyzer from 5 to 5 degrees across the range of possible values (0∘÷180∘0^{\circ} \div 180^{\circ}). For each position of the analyzer, write down in Table 4, the indication U(mV)U(mV) of the voltmeter coupled to the resistance R corresponding to the inverse current intensity value I(mA)I(mA) of the photodiode. The intensity value of this electrical current is directly proportional to the light intensity that reaches the photodiode. [1 т.]

4.2.2 Calibration of the electrical system for light intensity measurements

4.2.2.a. Identifies the correct position of cross-filters. Correct - if appropriate - the values of angle between the polarizer and the analyzer transmission directions. Fill in the values of this angle θ(∘)\theta(^{\circ}) in Table 4, used in the task 4.2.1.a. Also, fill in the same table the values cos⁡2θ\cos^2\theta, for all values of the angles measured and corrected. [0,5 т.]

4.2.2.b. Plot the graph of the dependence I(mA)=a⋅cos⁡2θ+bI(mA) = a \cdot \cos^2\theta + b. Name Graph 4, this graphical representation. [1 т.]

4.2.2.c. Determine the numerical values of the aa and bb parameters and indicate their physical meaning. [1 т.]

4.3 Polarimetric measurements

In optically active solutions, the angle β\beta of rotation of the polarization plane is proportional to the solution concentration c and the length d of the light pathway through the solution. In this part of the problem, you will experimentally check the dependence β∼d⋅c\beta \sim d \cdot c and determine the unknown concentration of a sugar solution in water.

Assemble the cuvette for the sugar solutions on the vertical holder. Align the laser beam so that the light falls on the photodiode without reflections on the walls of the cuvette or on the edges of the vertical support. Reverse the battery's polarity, so that the diode becomes reverse-biased. Since the cross-filter situation (minimum electrical signal) is easier to observe than the condition of the filters with parallel transmission axes (reverse current maximum), it is recommended to track the minimum electrical signal.

4.3.a. With the empty cuvette, and the analyzer positioned so that the needle indicates 90∘90^{\circ}, rotate the polarizer until the crossed filter situation is reached.

Using the syringe and the hose, add the liquid with the concentration c1c_1, step by step, so that the length of the fluid column increases each time by three centimeters. For each of the lengths d of the liquid column, write down the value of the indicated angle and determine the value of the angle β\beta of the polarization plane at which the minimum signal is achieved, which corresponds to the crossed polarizer-analyzer.

Write down in Table 5 the values of the d column lengths, the angles indicated by the indicator needle and the corresponding β\beta angles. [1 т.]

4.3.b. Plot the graph β=f(d)\beta = f(d). Name Graph 5, the graphical representation that you obtained in this task. [1 т.]

4.3.c. Measure the values of the angle β\beta for columns of equal lengths d=25 cmd = 25\ \mathrm{cm} of the solutions with the concentrations c1c_1 , c2c_2 , c3c_3 . Write down the numerical values in Table 6. [1 т.]

4.3.d. Plot the graph β=f(c)\beta = f(c) and name it Graph 6. [1 т.]

4.3.e. Measure the value of the angle β\beta for a column of length d=25 cmd = 25\ \mathrm{cm} of the unknown concentration solution cxc_x and notes the value obtained in the appropriate box on the Answer Sheet. Use the graphical representation obtained in the task 4.3.d., determine the value of unknown concentration cxc_x and write down the value obtained in the appropriate box on the Answer Sheet. [1 т.]

© Subject proposed by:
Prof. Dr. Delia DAVIDESCU
Conf. Univ. Dr. Adrian DAFINEI
Prof. Dr. Dan Ovidiu CROCNAN

Отговори

Решение


Оригинал в Архива: exp.pdf · официални решения: exp_sol.pdf