RMPh 2017, Теория, 27 октомври — Задача 3. On the propagation and generation of gravitational waves

Romanian Master of Physics 2017 — Theoretical Exam - October 27, 2017 · 27 октомври 2017 г. · 10 т.

Внимание: Бележка към темата

Printed year2017 is retained despite archive folder2018. Q2 alone prints October28 and a Problem1 footer; Q1/Q3 print October27/Problem3. The obtained key is titled Problem1 but contains the matching entire gravitational-wave question/key. Native key errors are retained: k=k x-hat despite z propagation; interchanged h+/h× identification; unresolved reference (??); eq18 f≥…0.29] and eq19 Φ≥0.2 J/m² despite upper-bound wording and the earlier0.07. No physical result or answer has been silently corrected.

Условие

The scope of this problem is to help you understand the properties of gravitational waves, whose discovery has recently been rewarded with the 2017 Nobel Prize in Physics. Part I of the problem will analyze the propagation of gravitational waves in close analogy with electromagnetic waves, while Part II will be concerned with estimating the amount of energy gravitational waves carry from the merger of two black holes.

Part I. (6 т.)

Numerous phenomena that occur when studying gravitational waves closely resemble those in the world of electromagnetism. This is due to the similarity between solutions to the Maxwell equations in vacuum,

∇⋅E⃗=∂Ex∂x+∂Ey∂y+∂Ez∂z=0,(1)\nabla \cdot \vec{E} = \frac{\partial E_x}{\partial x} + \frac{\partial E_y}{\partial y} + \frac{\partial E_z}{\partial z} = 0, \quad (1)
∇⋅B⃗=∂Bx∂x+∂By∂y+∂Bz∂z=0,(2)\nabla \cdot \vec{B} = \frac{\partial B_x}{\partial x} + \frac{\partial B_y}{\partial y} + \frac{\partial B_z}{\partial z} = 0, \quad (2)
∇×E⃗=(∂Ez∂y−∂Ey∂z)x^+(∂Ex∂z−∂Ez∂x)y^+(∂Ey∂x−∂Ex∂y)z^=−∂B⃗∂t,(3)\nabla \times \vec{E} = \left(\frac{\partial E_z}{\partial y} - \frac{\partial E_y}{\partial z}\right)\hat{x} + \left(\frac{\partial E_x}{\partial z} - \frac{\partial E_z}{\partial x}\right)\hat{y} + \left(\frac{\partial E_y}{\partial x} - \frac{\partial E_x}{\partial y}\right)\hat{z} = -\frac{\partial \vec{B}}{\partial t}, \quad (3)
∇×B⃗=(∂Bz∂y−∂By∂z)x^+(∂Bx∂z−∂Bz∂x)y^+(∂By∂x−∂Bx∂y)z^=1c2∂E⃗∂t,(4)\nabla \times \vec{B} = \left(\frac{\partial B_z}{\partial y} - \frac{\partial B_y}{\partial z}\right)\hat{x} + \left(\frac{\partial B_x}{\partial z} - \frac{\partial B_z}{\partial x}\right)\hat{y} + \left(\frac{\partial B_y}{\partial x} - \frac{\partial B_x}{\partial y}\right)\hat{z} = \frac{1}{c^2}\frac{\partial \vec{E}}{\partial t}, \quad (4)

which describe electromagnetic waves propagating freely, and solutions to the equation for gravitational waves propagating in vacuum,

−1c2∂2∂t2hij+∇2hij=−1c2∂2∂t2hij+(∂2hij∂x2+∂2hij∂y2+∂2hij∂z2)=0(5)-\frac{1}{c^2}\frac{\partial^2}{\partial t^2}\mathbf{h}_{ij} + \nabla^2\mathbf{h}_{ij} = -\frac{1}{c^2}\frac{\partial^2}{\partial t^2}\mathbf{h}_{ij} + \left(\frac{\partial^2\mathbf{h}_{ij}}{\partial x^2} + \frac{\partial^2\mathbf{h}_{ij}}{\partial y^2} + \frac{\partial^2\mathbf{h}_{ij}}{\partial z^2}\right) = 0 \quad (5)

Above, cc is the speed of light and E⃗\vec{E} and B⃗\vec{B} are the electric and magnetic field, respectively. hh can be understood as a 3×3 matrix whose elements represent perturbations in the "fabric" of space. The matrix needs to be symmetric (hij=hjih_{ij} = h_{ji}), with each line and column representing a direction in space: specifically, i,j=1,3‾i, j = \overline{1,3}, and 1 corresponds to x, 2 to y and 3 to z. Thus, for instance, the element h11h_{11} is associated to the xx component of the wave, h12h_{12} is associated to the xy component of the wave etc. The gravitational wave equation (5) thus applies independently to every element of the matrix hh.

Note that when taking the product between the matrix U and a vector E⃗\vec{E}, each element of the resulting vector E⃗′\vec{E}' is given by, (E⃗′)i=∑j=13Uij(E⃗)j(\vec{E}')_i = \sum_{j=1}^{3} U_{ij}(\vec{E})_j.

Note that when taking the transpose (UT)ij=Uji(U^T)_{ij} = U_{ji} for all i,j=1,3‾i, j = \overline{1,3}. When taking the product between two 3×3 matrices, A and B, (AB)ij=∑l=13AilBlj(AB)_{ij} = \sum_{l=1}^{3} A_{il}B_{lj} for every i,j=1,3‾i, j = \overline{1,3}.

a) [2 pts.] Show that for an electromagnetic wave propagating in the z-direction, E⃗(r⃗,t)=E0ei(ωt−kz)x^\vec{E}(\vec{r},t) = E_0 e^{i(\omega t - kz)}\hat{x} is a solution to Maxwell's equations in vacuum (1–4), where x^\hat{x} is the unit vector in the x-direction, and find the associated magnetic field B⃗(r⃗,t)\vec{B}(\vec{r},t). Along the way, prove that B⃗(r⃗,t)\vec{B}(\vec{r},t) needs to be pointing in the y-direction. Furthermore, show that k⃗×E⃗(r⃗,t)=ωB⃗(r⃗,t)\vec{k} \times \vec{E}(\vec{r},t) = \omega \vec{B}(\vec{r},t). [2 т.]

b) [1 pt.] Prove that the equation for gravitational waves also has a similar oscillating solution propagating in the z-direction, h=h0ei(ωt−kz)h = h_0 e^{i(\omega t - kz)}, where h0h_0 is a 3 × 3 matrix of constants. [1 т.]

c) [0.5 pts.] Show that in vacuum both electromagnetic waves and gravitational waves propagate at the speed of light. [0,5 т.]

d) [1 pt.] Similar to how Maxwell's equations impose a constraint that relates the electric field, E⃗\vec{E}, to the magnetic field B⃗\vec{B}, there are supplementary constrains that can be imposed for the matrix hh. Specifically, for a wave propagating in the z-direction one can impose that any component of the matrix related to the z-direction has to vanish (hi3=h3i=0h_{i3} = h_{3i} = 0 for i=1,3‾i = \overline{1,3}), and that the matrix is traceless (h11+h22+h33=0h_{11} + h_{22} + h_{33} = 0). Use these properties, together with the fact that the matrix is symmetric, to show that h0h_0 only has two independent components. Show that h0h_0 can be expressed as

h0=h+ϵ++h×ϵ×,(6)\mathbf{h}_0 = h_+\epsilon_+ + h_\times\epsilon_\times, \quad (6)

where h+h_+ și h×h_\times are two independent constants and ϵ+\epsilon_+ and ϵ×\epsilon_\times are given by

ϵ+=(1000−10000),ϵ×=(010100000).(7)\epsilon_+ = \begin{pmatrix} 1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \quad \epsilon_\times = \begin{pmatrix} 0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}. \quad (7)

[1 т.]

e) [1.5 pts.] In quantum mechanics, the spin of a particle is given by a number ss that describes the symmetry of the wave solution associated with the propagation of this particle. Specifically, the spin is the maximum number, ss, for which the wave solution is invariant under rotations of 3600/s360^0/s around the direction of propagation. The three-dimensional rotation matrix that performs a rotation of angle θ\theta around the z-axis is given by,

U=(cos⁡θ−sin⁡θ0sin⁡θcos⁡θ0001),(8)\mathbf{U} = \begin{pmatrix} \cos\theta & -\sin\theta & 0 \\ \sin\theta & \cos\theta & 0 \\ 0 & 0 & 1 \end{pmatrix}, \quad (8)

and transforms the electric and magnetic fields as, E⃗→U⋅E⃗\vec{E} \to U \cdot \vec{E}, and, B⃗→U⋅B⃗\vec{B} \to U \cdot \vec{B} respectively. The matrix hh transforms as, h→UhUTh \to UhU^T, where UTU^T is the transpose of UU.

Find the spin of the photon (the particle associated to electromagnetic waves) and that of the graviton (associated to gravitational waves). [1,5 т.]

Part II. (4 т.)

The black holes, whose merger was recently detected by the winners of the 2017 Nobel Prize in Physics, are extremely massive objects with strange physical properties. The first detection of gravitational waves came from the merger of two black holes each with a mass equal to M=30M = 30 solar masses located d=1.3⋅109d = 1.3\cdot10^9 light-years from Earth (1 solar mass is 1.98⋅1030 kg1.98\cdot10^{30}\ kg and 1 light year is 9.46⋅1015 m9.46\cdot10^{15}\ m).

a) [1.5 pts.] Assuming that the merger of the two black holes occurs while the black holes are close to being at rest and generates only gravitational waves, and nothing else, use the mass-energy relation to express the energy passing through a detector with the opening of 1 m², situated on Earth from those gravitational waves. Express your answer both analytically (in terms of the mass MM of each black hole, the distance dd and the speed of light cc) and numerically. [1,5 т.]

b) [2.5 pts.] The assumption that all the energy from the merger is converted only to gravitational waves can be easily refined using the laws of thermodynamics. Gravitational waves hold only negligible entropy while black holes carry huge amounts of entropy. The entropy of a single black hole of mass MM is given by, SBH=sM2S_{BH} = sM^2, where ss is related to fundamental constants. Argue that if two black holes violently collide to make one bigger black hole, then at most 29% of their initial rest energy can be radiated in gravitational waves. Thus, assuming that the two black holes are almost static during the collision, give a numerical upper bound for the energy flux determined on Earth from the black hole collision. Note that the assumption that the two black holes are static should only apply to the numerical result and no to the rest of the problem. [2,5 т.]

Отговори

Решение

Printed source attribution

The problem is attributed to Luca ILIESIU. The mixed Romanian și and all printed seven requests/6+4-point rubrics are retained.


Оригинал в Архива: T3.pdf · официални решения: T3_sol.pdf