USAAAO 2020, I кръг — Задача 12
USAAAO National Astronomy Olympiad First Round 02/10/2020-02/16/2020 · 10 февруари 2020 г. · 1 т.
Указания
This exam contains 8 pages and 30 questions. Each question is worth 1 point, so there are 30 points total. Students MUST take the exam between 02/10/2020-02/16/2020. Proctors must scan students’ responses by 11:59 pm PST on 02/16/2020.
PHYSICAL AND ASTRONOMICAL CONSTANTS
| c | Speed of light in vacuo | |
| e | Elementary charge | |
| Neutron rest mass | ||
| Proton rest mass | ||
| Electron rest mass | ||
| h | Planck’s constant | |
| Hubble’s constant | 70 (km/s)/Mpc | |
| k | Boltzmann’s constant | |
| b | Wien’s constant | |
| G | Gravitational constant | |
| Stefan-Boltzmann constant | ||
| First Radiation Constant | ||
| Second Radiation Constant | ||
| Avogadro constant | ||
| R | Gas constant | |
| Bohr radius | ||
| Bohr magneton | ||
| Solar mass | ||
| Solar radius | ||
| Solar luminosity | ||
| Solar temperature | 5770 K | |
| Earth mass | ||
| Mean Earth radius | ||
| Earth moment of Inertia | ||
| R☾ | Mean Moon radius | |
| M♃ | Mean Jupiter mass | |
| R♃ | Mean Jupiter radius | |
| a♃ | Mean orbital radius of Jupiter | 5.2 AU |
| a☾ | Mean semimajor axis Moon orbit | |
| 1 light year | ||
| 1 AU | Astronomical Unit | |
| 1 pc | Parsec | |
| 1 year | ||
| 1 erg |
ENERGY CONVERSION : 1 joule (J) = electronvolts (eV)
Условие
Knowing that the distance between the Sun and Uranus is km and Uranus’ revolution period is 17h 14 min, determine the approximate amount of time that the Sun is above the horizon for an observer on the Uranus in the following situations:
I. At the South pole
II. At latitude 5’N when the declination of the Sun is N
A. I = 84 years and II = 17h 14 min
B. I = 21 years and II = 12h 47 min
C. I = 42 years and II = 9h 28 min
D. I = 21 years and II = 8h 37 min
E. I = 42 years and II = 14h 53 min
Отговори
- I = 42 years and II = 9h 28 min
Решение
C: I = 42 years and II = 9h 28 min
Using the 3rd law of Kepler we find that the period of Uranus orbit is approximately 84 years. Knowing that Uranus is tilted almost 90, we know that the Sun is above the South Pole’s horizon of this planet for almost half of the orbital period, so the answer for part I is 42 years. II. Using spherical trigonometry to find the time it takes to the Sun leave the horizon and and cross the meridian we have:
The total time the Sun is above the horizon will be 24.73 = 9.46h = 9h28min.
Оригинал в Архива: 2020_usaaao_first_round.pdf · официални решения: usaaao_first_round_answer_key_2020.pdf