USAAAO 2020, I кръг — Задача 6
USAAAO National Astronomy Olympiad First Round 02/10/2020-02/16/2020 · 10 февруари 2020 г. · 1 т.
Указания
This exam contains 8 pages and 30 questions. Each question is worth 1 point, so there are 30 points total. Students MUST take the exam between 02/10/2020-02/16/2020. Proctors must scan students’ responses by 11:59 pm PST on 02/16/2020.
PHYSICAL AND ASTRONOMICAL CONSTANTS
| c | Speed of light in vacuo | |
| e | Elementary charge | |
| Neutron rest mass | ||
| Proton rest mass | ||
| Electron rest mass | ||
| h | Planck’s constant | |
| Hubble’s constant | 70 (km/s)/Mpc | |
| k | Boltzmann’s constant | |
| b | Wien’s constant | |
| G | Gravitational constant | |
| Stefan-Boltzmann constant | ||
| First Radiation Constant | ||
| Second Radiation Constant | ||
| Avogadro constant | ||
| R | Gas constant | |
| Bohr radius | ||
| Bohr magneton | ||
| Solar mass | ||
| Solar radius | ||
| Solar luminosity | ||
| Solar temperature | 5770 K | |
| Earth mass | ||
| Mean Earth radius | ||
| Earth moment of Inertia | ||
| R☾ | Mean Moon radius | |
| M♃ | Mean Jupiter mass | |
| R♃ | Mean Jupiter radius | |
| a♃ | Mean orbital radius of Jupiter | 5.2 AU |
| a☾ | Mean semimajor axis Moon orbit | |
| 1 light year | ||
| 1 AU | Astronomical Unit | |
| 1 pc | Parsec | |
| 1 year | ||
| 1 erg |
ENERGY CONVERSION : 1 joule (J) = electronvolts (eV)
Условие
A 13 kg telescope is mounted on a tripod such that the angle between tripod legs is . How much is the force exerted on each leg? Gravitational acceleration (g) is 9.8 .
A. 42.5
B. 44.5
C. 49
D. 24.5
E. 40.5
Отговори
44.5
The answer is in newtons (the solution gives F = 44.5N).
Решение
B: 44.5
If we take as an angle between the gravitational force and one of the legs, then the force exerted on each leg will be . If we project legs and vector of gravitational force (G) on a spherical sphere then can be derived using a spherical triangle with vertices leg1(A), leg2(B) and leg3(C). We have . Drawing a vertical line from G to the side of and naming it H, we have , and . Using the spherical law of sines, , so F = 44.5N.
Оригинал в Архива: 2020_usaaao_first_round.pdf · официални решения: usaaao_first_round_answer_key_2020.pdf