USAAAO 2021, I кръг — Задача 27
USAAAO 2021 - First Round · 30 януари 2021 г.
PHYSICAL AND ASTRONOMICAL CONSTANTS
| c | Speed of light in vacuum | |
| e | Elementary charge | |
| m | Neutron rest mass | |
| m | Proton rest mass | |
| m | Electron rest mass | |
| m | Helium-4 rest mass | |
| h | Planck’s constant | |
| H | Hubble’s constant | 70 (km/s)/Mpc |
| k | Boltzmann’s constant | |
| b | Wien’s constant | |
| G | Gravitational constant | |
| Stefan-Boltzmann constant | ||
| c | First Radiation Constant | |
| c | Second Radiation Constant | |
| N | Avogadro constant | |
| R | Gas constant | |
| a | Bohr radius | |
| Bohr magneton | ||
| M | Solar mass | |
| R | Solar radius | |
| L | Solar luminosity | |
| T | Solar temperature | 5770 K |
| M | Earth mass | |
| R | Mean Earth radius | |
| I | Earth moment of Inertia | |
| R☾ | Mean Moon radius | |
| M♃ | Mean Jupiter mass | |
| R♃ | Mean Jupiter radius | |
| a♃ | Mean orbital radius of Jupiter | 5.2 AU |
| a☾ | Mean semimajor axis Moon orbit | |
| 1 light year | ||
| 1 AU | Astronomical Unit | |
| 1 pc | Parsec | |
| 1 year | ||
| 1 sidereal day | 86164 s | |
| 1 erg | ||
| 1 bar |
ENERGY CONVERSION : 1 joule (J) = electronvolts (eV)
Условие
When binary systems are really close together, they can execute an accretion process, in which one star (called the primary star) ”eats” the mass of the other (called the secondary star), whose mass spirals down into the primary star, creating an accretion disk!
For an accretion disk with the outer edge from the center of the primary star (radius and mass ), calculate the energy lost by a test mass (mass ) where it touches the primary star from where it first enters the accretion disk.
Consider the orbits to be Keplerian.
(a)
(b)
(c)
(d)
(e)
Отговори
The problem was CANCELED. The solutions document reprints option (d) as 1/3 GMm/R and gives Answer: D; on test day option (d) was 2/3 GMm/R (as in the problems document), so none of the printed options was correct.
Решение
Let the total energy when the test mass enters the disk be:
and the total energy when the test mass touches the star be:
Hence, the difference between the two will be:
Answer: D
On test day, item (d) was which was incorrect.
Оригинал в Архива: usaaao2021_exam1.pdf · официални решения: usaaao2021_exam1_solutions.pdf