USAAAO 2025, I кръг — Задача 26
USAAAO 2025 - First Round · 8 февруари 2025 г.
Внимание: Бележка към темата
All 30 separately numbered original first-round multiple-choice questions and their matching official explanations/answer letters are retained. The printed explanations for Questions 2 and 3 stop before a promised formula; Question 26 refers to a following triangle absent from its native solution page. No missing expression or diagram is reconstructed. Native scientific discrepancies and ambiguous formula notation remain literal and are explicitly attributed in local source notes. A separate two-page common USAAAO archive constants/reference table is included with its own source identity; it is undated in the catalogue, and its use as the exact 2025 attachment is not established. No separate dated instructions, answer sheet or constants companion is present in the 2025 archive folder. No point total or time limit is printed in these two exam booklets.
Original first-round date and writers
USAAAO 2025 - First Round
February 8th, 2025
Writers: Abhay Bestrapalli, Sidhant Chaliha, Ferdinand, Ved Gund, Hagan Hensley, Yehong Jiang, Alexander Li, Joe McCarty, Lucas Carrit Delgado Pinheiro, Sahil Pontula.
Common archive reference — Table of Physical Constants
This separate common USAAAO archive reference is undated in the catalogue. Its use as the exact 2025 exam attachment is not established.
| Quantity | Symbol | Value |
|---|---|---|
| Electron rest mass | ||
| Proton rest mass | ||
| Electronic charge | ||
| Speed of light in free space | ||
| Permeability of free space | ||
| Permittivity of free space | ||
| Planck’s constant | ||
| Reduced Planck’s constant | ||
| Boltzmann’s constant | ||
| Gas constant | ||
| Molar gas constant | ||
| Avogadro’s number | ||
| Standard molar volume | ||
| Unified atomic mass unit ( scale) | ||
| Mass of hydrogen atom | ||
| Bohr magneton | or | |
| Nuclear magneton | or | |
| Proton magnetic moment | ||
| Neutron magnetic moment | ||
| Bohr radius | ||
| Fine structure constant | ||
| Compton wavelength of electron | ||
| Rydberg’s constant | ||
| Stefan-Boltzmann constant | ||
| Radiation density constant | ||
| Gravitational constant |
Rest masses of some leptons and hadrons in :
0.5110, 105.66, 1777, 134.98, 139.57, 493.7, 497.7, 547, 1865, 1869, p 938.3, n 939.6, 1115.7, 1189, 1193, 1197, 1315, 1321, 1672, , .
| Quark | Charge | Mass () | |||||
|---|---|---|---|---|---|---|---|
| u | 0 | 0 | 0 | 0 | |||
| d | 0 | 0 | 0 | 0 | |||
| c | 0 | 0 | +1 | 0 | 0 | ||
| s | 0 | -1 | 0 | 0 | 0 | ||
| t | 0 | 0 | 0 | 0 | +1 | 174.3 | |
| b | 0 | 0 | 0 | -1 | 0 | 4.2 |
Common archive reference — Astrophysical Data and identities
Astrophysical Data
| Quantity | Symbol | Value |
|---|---|---|
| 1 astronomical unit | AU | |
| 1 parsec | pc | |
| Luminosity of Sun | ||
| Mass of Sun | ||
| Radius of Sun | ||
| Mass of Earth | ||
| Radius of Earth |
Other data and conversion factors
| Quantity | Symbol | Value |
|---|---|---|
| 1 ångstrom | Å | |
| 1 fermi | fm | |
| 1 barn | b | |
| 1 pascal | Pa | |
| 1 standard atmosphere | ||
| Standard acceleration due to gravity | ||
| 1 electron volt | eV | |
| Wavelength of 1 eV photon |
Trigonometrical identities
In a triangle ABC,
and
Prefixes
| Prefix | Name | Factor |
|---|---|---|
| T | tera | |
| G | giga | |
| M | mega | |
| k | kilo | |
| c | centi | |
| m | milli | |
| micro | ||
| n | nano | |
| p | pico | |
| f | femto |
Source note: The common table prints and . The 2025 question14/key15 use 9.81 and key7 uses 6371 km; those original exam values are preserved separately.
Условие
Two exoplanets, A and B, have circular orbits around the same central star. Suppose that the ascending nodes of the orbits are located at the same ecliptic longitude, defined analogously as the one for the solar system, and that both planets are at that point in the beginning. How long will it take for the planets to have an equal, common ecliptic longitude again, knowing that the inclinations of their orbits are and , and that their periods are and ?
(a) 42 days
(b) 44 days
(c) 46 days
(d) 48 days
(e) 50 days
Отговори
- E
Решение
Внимание: Непълно решение
The printed text references a following spherical triangle, but no such diagram is present on the original solution page20. No diagram is invented.
From the following spherical triangle, letting be the ecliptic longitude of a planet and its angular velocity along its orbit:
Hence, when the ecliptic longitudes are the same again:
Since :
Answer: E
Source note: The printed text references a following spherical triangle, but no such diagram is present on the original solution page20. No diagram is invented.
Теми и трудност
Оценена трудност: 4/5.
Небесна механика · Небесна сфера и сферична астрономия · Орбитално движение · Небесни координати
Предпоставки: Гимназиална подготовка, Разширена олимпиадна подготовка
Оригинал в Архива: exam_2025.pdf · официални решения: sol_2025.pdf · допълнителни данни: physical-constants.pdf