USAPhO 2016, Полуфинал — Задача 1. Question A1

USA Physics Olympiad Exam — Part A / Part B · 25 т.

Внимание: Бележка към темата

The native worked key contains printed mathematical inconsistencies at A1(b), B1 and B2(a)(iii)/(c)(ii); the source formulas and adjacent reasoning are retained as printed. The A3 key graphs omit the requested event-letter labels and do not draw the stopped-rod world-line changes; no new answer labels or lines have been invented. Exact originals and detailed source-defect evidence accompany this transcription.

Important Instructions for the Exam Supervisor — DO NOT DISTRIBUTE THIS PAGE
  • This examination consists of two parts: Part A has four questions and is allowed 90 minutes; Part B has two questions and is allowed 90 minutes.

  • The first page that follows is a cover sheet. Examinees may keep the cover sheet for both parts of the exam.

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  • Ideally the test supervisor will divide the question paper into 4 parts: the cover sheet (page 2), Part A (pages 3-6), Part B (pages 8-9), and several answer sheets for one of the questions in Part A (pages 11-12). Examinees should be provided parts A and B individually, although they may keep the cover sheet. The answer sheets should be printed single sided!

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USA Physics Olympiad Exam — Instructions

DO NOT OPEN THIS TEST UNTIL YOU ARE TOLD TO BEGIN - Work Part A first. You have 90 minutes to complete all four problems. Each question is worth 25 points. Do not look at Part B during this time. - After you have completed Part A you may take a break. - Then work Part B. You have 90 minutes to complete both problems. Each question is worth 50 points. Do not look at Part A during this time. - Show all your work. Partial credit will be given. Do not write on the back of any page. Do not write anything that you wish graded on the question sheets. - Start each question on a new sheet of paper. Put your AAPT ID number, your name, the question number and the page number/total pages for this problem, in the upper right hand corner of each page. For example,

AAPT ID # Doe, Jamie A1 - 1/3

  • A hand-held calculator may be used. Its memory must be cleared of data and programs. You may use only the basic functions found on a simple scientific calculator. Calculators may not be shared. Cell phones, PDA’s or cameras may not be used during the exam or while the exam papers are present. You may not use any tables, books, or collections of formulas. - Questions with the same point value are not necessarily of the same difficulty. - In order to maintain exam security, do not communicate any information about the questions (or their answers/solutions) on this contest until after April 15, 2016.
Possibly Useful Information. You may use this sheet for both parts of the exam.
InformationValue
gg9.8 N/kg9.8\ \mathrm{N/kg}
k=1/(4πε0)k=1/(4\pi\varepsilon_0)8.99×109 N⋅m2/C28.99\times10^9\ \mathrm{N\cdot m^2/C^2}
cc3.00×108 m/s3.00\times10^8\ \mathrm{m/s}
NAN_A6.02×1023 (mol)−16.02\times10^{23}\ (\mathrm{mol})^{-1}
σ\sigma5.67×10−8 J/(s⋅m2⋅K4)5.67\times10^{-8}\ \mathrm{J/(s\cdot m^2\cdot K^4)}
1 eV1\ \mathrm{eV}1.602×10−19 J1.602\times10^{-19}\ \mathrm J
mem_e9.109×10−31 kg=0.511 MeV/c29.109\times10^{-31}\ \mathrm{kg}=0.511\ \mathrm{MeV}/c^2
sin⁡θ\sin\theta≈θ−16θ3\approx\theta-\frac16\theta^3 for ∣θ∣≪1\vert \theta\vert \ll1
GG6.67×10−11 N⋅m2/kg26.67\times10^{-11}\ \mathrm{N\cdot m^2/kg^2}
km=μ0/(4π)k_m=\mu_0/(4\pi)10−7 T⋅m/A10^{-7}\ \mathrm{T\cdot m/A}
kBk_B1.38×10−23 J/K1.38\times10^{-23}\ \mathrm{J/K}
R=NAkBR=N_Ak_B8.31 J/(mol⋅K)8.31\ \mathrm{J/(mol\cdot K)}
ee1.602×10−19 C1.602\times10^{-19}\ \mathrm C
hh6.63×10−34 J⋅s=4.14×10−15 eV⋅s6.63\times10^{-34}\ \mathrm{J\cdot s}=4.14\times10^{-15}\ \mathrm{eV\cdot s}
(1+x)n(1+x)^n≈1+nx\approx1+nx for ∣x∣≪1\vert x\vert \ll1
cos⁡θ\cos\theta≈1−12θ2\approx1-\frac12\theta^2 for ∣θ∣≪1\vert \theta\vert \ll1

Условие

Part A

The Doppler effect for a source moving relative to a stationary observer is described by

f=f01−(v/c)cos⁡θf=\frac{f_0}{1-(v/c)\cos\theta}

where ff is the frequency measured by the observer, f0f_0 is the frequency emitted by the source, vv is the speed of the source, cc is the wave speed, and θ\theta is the angle between the source velocity and the line between the source and observer. (Thus θ=0\theta=0 when the source is moving directly towards the observer and θ=π\theta=\pi when moving directly away.)

A sound source of constant frequency travels at a constant velocity past an observer, and the observed frequency is plotted as a function of time:

Complete native observed-frequency scatter plot: all 29 circle data points, Frequency(Hz)/Time(s) axes, 420–450Hz/0–14s ticks, grid and Observed Frequency legend.

The experiment happens in room temperature air, so the speed of sound is 340 m/s340\ \mathrm{m/s}.

a. What is the speed of the source?

b. What is the smallest distance between the source and the observer?

Решение


Оригинал в Архива: USAPhO-2016.pdf · официални решения: USAPhO-2016-Solutions.pdf