GPhO 2016, Теория — Задача 3. Magnetars

The 1st Gulf Physics Olympiad — Theoretical Competition · 21 март 2016 г. · 9 т.

Указания
  • The examination lasts for 5 hours. There are 3 problems worth in total 30 points. Please note that the point values of the three theoretical problems are not equal.
  • You must not open the envelope with the problems before the signal of the beginning of competition.
  • You are not allowed to leave your working place without permission. If you need any assistance (broken calculator, need to visit a restroom, etc), please raise your hand until an organizer arrives.
  • Use only the front side of the sheets of paper.
  • For each problem, there are dedicated Solution Sheets (see header for the number and pictogram). Write your solutions onto the appropriate Solution Sheets. For each Problem, the Solution Sheets are numbered; use the sheets according to the enumeration. Always mark which Problem Part and Question you are dealing with. Copy the final answers into the appropriate boxes of the Answer Sheets. There are also Draft papers; use these for writing things which you don’t want to be graded. If you have written something that you don’t want to be graded onto the Solution Sheets (such as initial and incorrect solutions), cross these out.
  • If you need more paper for a certain problem, please raise your hand and tell an organizer the problem number; you are given two Solution sheets (you can do this more than once).
  • You should use as little text as possible: try to explain your solution mainly with equations, numbers, symbols and diagrams. Though in some places textual explanation may be unavoidable.
  • After the signal signifying the end of examination you must stop writing immediately. Put all the papers into the envelope at your desk. You are not allowed to take any sheet of paper out of the room. If you have finished solving before the final sound signal, please raise your hand.

Условие

Magnetic fields are everywhere around us. Some typical magnetic B-field values: Earth’s magnetic field: 25−60 μT25 - 60\ \mu\mathrm{T}; at Sunspots: 0.3 T0.3\ \mathrm{T}; strong permanent magnets: around 1 T1\ \mathrm{T}; continuously maintained magnetic fields in laboratory: up to 45 T45\ \mathrm{T}; neutron stars and magnetars: up to 1011 T10^{11}\ \mathrm{T}. In what follows we study few aspects of strong magnetic fields.

Magnetic field energy density w=B212μμ0w = B^2\frac{1}{2\mu\mu_0}, where μ0≈1.3×10−6 N/A2\mu_0 \approx 1.3\times10^{-6}\ \mathrm{N/A^2} is the vacuum permeability, and μ\mu — the relative permeability of the medium. System tries to move towards a lower energy state and so ferromagnetic materials with μ≫1\mu \gg 1 are pulled towards regions with strong magnetic fields, and diamagnetic materials with μ<1\mu < 1 are pushed out. For diamagnetic materials, the magnetic susceptibility χ=μ−1\chi = \mu - 1 is small, ∣χ∣≪1|\chi| \ll 1, and so the effect is small unless the field is strong. Water is a diamagnetic with χ=−9×10−6\chi = -9\times10^{-6} and animals are mostly made of water. So, a frog can levitate in a magnetic field if the field is strong enough, see the photo.

Photograph of a small frog levitating inside the round bore of a strong magnet; credit line “© Lijnis Nelemans”.
Three cross-sections of the star: an orange-brown outer shell (labelled “outer shell”) around a yellow interior with a small orange neutron star at the centre; in the first the field lines are straight radial arrows, in the second they are curved into spirals, in the third they are wound into a tight spiral of many turns.

i. Let the frog height hfh_f be not more than h0=10 mmh_0 = 10\ \mathrm{mm}, and let us assume simplifyingly that the squared magnetic field depends linearly on height zz, see figure. Find how strong magnetic field B0B_0 (in Teslas) is needed to keep this frog in levitation. Assume that the frog is made entirely of water (density ρ=1000 kg/m3\rho = 1000\ \mathrm{kg/m^3}); free fall acceleration g=9.8 m/s2g = 9.8\ \mathrm{m/s^2}. Hint: for ∣χ∣≪1|\chi| \ll 1, we can write w≈B21−χ2μ0w \approx B^2\frac{1-\chi}{2\mu_0}; hence, the energy density associated with the presence of water is Δw=B21−χ2μ0−B212μ0=−B2χ2μ0\Delta w = B^2\frac{1-\chi}{2\mu_0} - B^2\frac{1}{2\mu_0} = -B^2\frac{\chi}{2\mu_0}. [1,5 т.]

Graph of B² against height z: B² starts at B0² at z = 0 and decreases linearly (red line) to 0 at z = h0, then stays at 0; axes labelled B² and z, origin 0.

Stars are made of a plasma which is a good electrical conductor. Because of that, magnetic field lines behave as if being “frozen” into the moving plasma (this follows from the Faraday’s induction law and Kirchoff’s voltage law: due to the absence of electrical resistance, the voltage drop along a closed fictitious contour inside the plasma must be zero, hence the magnetic flux cannot change). If a star were to collapse into a neutron star, this effect would lead to an instantaneous increase of the magnetic field, see the sketch of the magnetic field lines before and after the collapse (recall that magnetic field strength is proportional to the density of field lines).

ii. Assuming that the polar magnetic field of a star is Bs=100 μTB_s = 100\ \mu\mathrm{T} and its average density ρs=1400 kg/m3\rho_s = 1400\ \mathrm{kg/m^3}, what would be its polar magnetic field strength BcB_c after its collapse into a neutron star due to the compression of magnetic field lines as depicted above? The neutron star density ρn=5×1017 kg/m3\rho_n = 5\times10^{17}\ \mathrm{kg/m^3}. [1 т.]

iii. In reality, magnetic fields of neutron stars are generated differently. Let us consider a very simplified model. Interior part of the star has collapsed to a neutron star’s size and density, but the exterior parts remains of the same size. Assume that before the collapse, the star was rotating as a solid body with angular speed ωs\omega_s. Express the new angular speed of the interior part of the star ωn\omega_n in terms of ωs\omega_s, ρs\rho_s and ρn\rho_n. [1 т.]

iv. Rotation speeds of the inner- and outer parts are different, hence the field lines will be stretched, see figure.

For the sake of simplicity: (a) we use 2-dimensional geometry, i.e. consider stars as being cylindrical; (b) while the initial field was a dipole field, we assume that it was cylindrically symmetric as shown in figure; (c) endpoints of field lines are attached to the inner cylinder (the neutron star) and to the outer cylindrical shell (the remnant of the original star). Let the initial magnetic field at the outer shell be B0B_0. Express the magnetic field BB as a function of time tt in the region where field lines are being stretched for t≫1/ωnt \gg 1/\omega_n in terms of B0B_0 and ωn\omega_n. [1,5 т.]

v. So, the energy is converted during the star collapse as follows: gravitational energy is converted into kinetic one (let us neglect thermal energy), which is later on converted into the magnetic one. Based on this scenario, estimate the maximal strength of the magnetic field Bmax⁡B_{\max} for a neutron star of mass Mn=4×1030 kgM_n = 4\times10^{30}\ \mathrm{kg} and radius Rn=13 kmR_n = 13\ \mathrm{km}. Recall that G=6.67×10−11 m3s−2kg−1G = 6.67\times10^{-11}\ \mathrm{m^3s^{-2}kg^{-1}}. [1 т.]

Sketch: a large yellow star labelled “before collapse” crossed by parallel oblique magnetic field lines, and a small hatched star labelled “after collapse” with densely packed field lines.

vi. Very strong magnetic fields affect chemical properties of matter by changing the shape of electron orbits. This happens when the Lorenz force acting on an orbital electron becomes stronger than the Coulomb force due to the atomic nucleus. Estimate the strength of the magnetic field BHB_H needed to distort the electron orbit of an hydrogen atom which has radius RH=5×10−11 mR_H = 5\times10^{-11}\ \mathrm{m}. Note that 14πε0=9×109 m/F\frac{1}{4\pi\varepsilon_0} = 9\times10^9\ \mathrm{m}/F, e=1.6×10−19 Ce = 1.6\times10^{-19}\ \mathrm{C}, and electron mass me=9.1×10−31 kgm_e = 9.1\times10^{-31}\ \mathrm{kg}. [1 т.]

vii. In very strong magnetic fields, atomic electron clouds take cylindrical shape. Estimate the length-to-diameter ratio κ=l/d\kappa = l/d of such electron clouds for hydrogen atoms near a neutron star, in magnetic field Bn=108 TB_n = 10^8\ \mathrm{T}. Note that the Planck’s constant h=6.6×10−34 J⋅sh = 6.6\times10^{-34}\ \mathrm{J\cdot s}. Hint: the radius of the cyclotron orbit for an electron in quantum-mechanical ground state can be estimated using uncertainty principle. [2 т.]

Отговори

Решение


Оригинал в Архива: th.pdf · официални решения: th_sol.pdf