IOAA 2015, Теория, дълги задачи, английски — Задача 3

International Olympiad on Astronomy and Astrophysics 2015, Central Java - Indonesia — Long Problems

Внимание: Бележка към темата

The revised official marking scheme is primary. Earlier image-key questions and marking weights differ and are labelled separately. The revised key leaves problem 3(d) blank; the earlier distance derivation adds an assumption absent from the final question. Printed algebraic inconsistencies are retained.

Instruction — Theoretical Round
  1. Write your answer on the answer-sheet only. You can use more than one sheet for one problem. Please ask the organizer for the additional answer-sheets.

  2. Different problems should be done on different sheets.

  3. You can use your own calculator without program and graphic facility.

  4. You can ask the organizer for rough paper.

Astronomical and Physical Constants — 20150729
ConstantValue
Astronomical unit (AU)1.4960×1011 m1.4960\times10^{11}\ \mathrm m
Light year (ly)9.4605×1015 m=63 240 au9.4605\times10^{15}\ \mathrm m=63\,240\ \mathrm{au}
Parsec (pc)3.0860×1016 m=206 265 au3.0860\times10^{16}\ \mathrm m=206\,265\ \mathrm{au}
Jansky (Jy)10−26 W m−2 Hz−110^{-26}\ \mathrm{W\,m^{-2}\,Hz^{-1}}
1 Sidereal year365.2564 solar days
1 Tropical year365.2422 solar days
1 Calendar year365.2425 solar days
1 Sidereal day23h 56m 04s.09123^{\mathrm h}\ 56^{\mathrm m}\ 04^{\mathrm s}.091
1 Solar day24h 03m 56s.55524^{\mathrm h}\ 03^{\mathrm m}\ 56^{\mathrm s}.555 units of sidereal time
1 Å10−10 m10^{-10}\ \mathrm m
1 erg10−7 J10^{-7}\ \mathrm J
1 dyne10−5 N10^{-5}\ \mathrm N
Mass of Earth5.9736×1024 kg5.9736\times10^{24}\ \mathrm{kg}
Mean radius of Earth6.371×106 m6.371\times10^6\ \mathrm m
Equatorial radius of Earth6.378×106 m6.378\times10^6\ \mathrm m
Mean velocity of Earth on its orbit29.783 km s−129.783\ \mathrm{km\,s^{-1}}
Mass of Moon7.3490×1022 kg7.3490\times10^{22}\ \mathrm{kg}
Radius of Moon1.737×106 m1.737\times10^6\ \mathrm m
Mass of Jupiter1.89813×1027 kg1.89813\times10^{27}\ \mathrm{kg}
Mean Earth – Moon distance3.844×108 m3.844\times10^8\ \mathrm m
Mass of Sun1.98892×1030 kg1.98892\times10^{30}\ \mathrm{kg}
Radius of Sun6.96×108 m6.96\times10^8\ \mathrm m
Effective temperature of the Sun5780 K
Luminosity of the Sun3.96×1026 J s−13.96\times10^{26}\ \mathrm{J\,s^{-1}}
Solar constant1366 W m−21366\ \mathrm{W\,m^{-2}}
Brightness of the Sun in V-band−26.8 mag.
Absolute brightness of the Sun in V-band4.75 mag.
Absolute bolometric brightness of Sun4.72 mag.
Angular diameter of the Sun30′
Speed of light in vacuum (c)2.9979×108 m s−12.9979\times10^8\ \mathrm{m\,s^{-1}}
Gravitational constant (G)6.6738×10−11 N m2 kg−26.6738\times10^{-11}\ \mathrm{N\,m^2\,kg^{-2}}
Boltzmann constant (k)1.381×10−23 m kg s−2 K−11.381\times10^{-23}\ \mathrm{m\,kg\,s^{-2}\,K^{-1}}
Universal gas constant (R)8.31 J K−1 mol−18.31\ \mathrm{J\,K^{-1}\,mol^{-1}}
Stefan–Boltzmann constant (σ)5.6704×10−8 kg s−3 K−45.6704\times10^{-8}\ \mathrm{kg\,s^{-3}\,K^{-4}}
Planck constant (h)6.6261×10−34 J s6.6261\times10^{-34}\ \mathrm{J\,s}
Wien's constant (b)2.8978×10−3 m K2.8978\times10^{-3}\ \mathrm{m\,K}
Hubble constant (H₀)70 km s−1 Mpc−170\ \mathrm{km\,s^{-1}\,Mpc^{-1}}
Astronomical and Physical Constants — continuation
ConstantValue
electron charge (e)1.602×10−19 C1.602\times10^{-19}\ \mathrm C
Mass of hydrogen atom1.67×10−27 kg1.67\times10^{-27}\ \mathrm{kg}
Current inclination of the ecliptic (ε)23º 26.3′
Coordinates of the northern ecliptic pole for epoch 2000.0 (αE, δE)18h 00m 00s,+66∘ 33.6′18^{\mathrm h}\ 00^{\mathrm m}\ 00^{\mathrm s},+66^{\circ}\ 33.6^{\prime}
Coordinates of the northern galactic pole for epoch 2000.0 (αG, δG)12h 51m,+27∘ 08′12^{\mathrm h}\ 51^{\mathrm m},+27^{\circ}\ 08^{\prime}

You can try to solve an equation x=f(x)x=f(x) using iteration: xn+1=f(xn)x_{n+1}=f(x_n).

Basic equations of spherical trigonometry

sin⁡asin⁡B=sin⁡bsin⁡A\sin a\sin B=\sin b\sin A
sin⁡acos⁡B=cos⁡bsin⁡c−sin⁡bcos⁡ccos⁡A,\sin a\cos B=\cos b\sin c-\sin b\cos c\cos A,
cos⁡a=cos⁡bcos⁡c+sin⁡bsin⁡ccos⁡A.\cos a=\cos b\cos c+\sin b\sin c\cos A.

Rayleigh-Jeans formula (long wavelength approximation of Planck’s Law):

Bν(T)=2kTν2c2B_\nu(T)=\frac{2kT\nu^2}{c^2}

Условие

Suppose a static spherical star consists of NN neutral particles with radius RR (see Figure 3).

Sphere of radius R centred at the origin of x, y, z axes, with a dotted equator; a dashed radius R makes polar angle θ with the z axis and its projection onto the x-y plane makes azimuthal angle ϕ.
Figure 3

with 0≤θ≤π0 \le \theta \le \pi , 0≤ϕ≤2π0 \le \phi \le 2\pi , satisfying the following equation of states

PV=Nk TR−T0ln⁡(TR/T0)(1)PV = N k \,\frac{T_R - T_0}{\ln(T_R/T_0)} \qquad (1)

where PP and VV are the pressure inside the star and the volume of the star respectively, kk is the Boltzmann constant. TRT_R and T0T_0 are the temperatures at the surface r=Rr = R and the temperature at the center r=0r = 0 respectively. Assume that TR≤T0T_R \le T_0.

a. Simplify the stellar equation of state (1) if ΔT=TR−T0≈0\Delta T = T_R - T_0 \approx 0 (this is called ideal star)
(Hint: Use the approximation ln⁡(1+x)≈x\ln(1 + x) \approx x for small xx)

Suppose the star undergoes a quasi-static process, in which it may slightly contract or expand, such that the above stellar equation of state (1) still holds.

The star satisfies first law of thermodynamics

Q=ΔMc2+W(2)Q = \Delta M c^2 + W \qquad (2)

where QQ, MM, and WW are heat, mass of the star, and work respectively, while cc is the light speed in the vacuum and ΔM≡Mfinal−Minitial\Delta M \equiv M_{\mathrm{final}} - M_{\mathrm{initial}} .

In the following we assume T0T_0 to be constant, while TR≡TT_R \equiv T varies.

b. Find the heat capacity of the star at constant volume CvC_v in term of MM and at constant pressure CpC_p expressed in CvC_v and TT (Hint: Use the approximation (1+x)n≈1+nx(1 + x)^n \approx 1 + nx for small xx)

Assuming that CvC_v is constant and the gas undergo the isobaric process so the star produces the heat and radiates it outside to the space.

c. Find the heat produced by the isobaric process if the initial temperature and the final temperature are TiT_i and TfT_f , respectively.

d. Suppose there is an observer far away from the star. Using information from part c., estimate the distance of the observer from the star.

For the next parts, assume the star is the Sun.

e. If the sunlight is monochromatic with frequency 5×10145 \times 10^{14} Hz, estimate the number of photons radiated by the Sun per second.

f. Calculate the heat capacity CvC_v of the Sun assuming its surface temperature varies from 5500 K to 6000 K in one second.

Basic equations of spherical trigonometry — reference diagram

Spherical triangle with vertices A,B,C and opposite sides a,b,c.

Решение

Внимание: Непълно решение

The revised official key leaves final problem 3(d) blank (15 points). The earlier image edition gives a distance derivation only after adding a 0.1% temperature-error assumption absent from the final question; it is retained separately, not presented as a complete final-edition answer.


Оригинал в Архива: Long_problem_Final_EN.pdf · официални решения: Long Problem Solution-Marking Scheme [Revised] - 310715 - 13.58.pdf · допълнителни данни: long_sol_1.png · допълнителни данни: long_sol_2.png · допълнителни данни: long_sol_3.png · допълнителни данни: long_sol_4.png · допълнителни данни: long_sol_5.png · допълнителни данни: long_sol_6.png · допълнителни данни: long_sol_7.png · допълнителни данни: long_sol_8.png · допълнителни данни: long_sol_9.png · допълнителни данни: long_sol_10.png · допълнителни данни: 9th IOAA Constants Table 20150729.pdf · допълнителни данни: constants.pdf · допълнителни данни: instructions.docx