IOM 2021, Блиц — Задача 47

The Blitz-contest of IOM-2021

Условие

Galvanic cell: an Fe electrode in a beaker labelled “0,1M Fe(NO3)2” and an Ag electrode in a beaker labelled “1M AgNO3”, connected by a salt bridge and by wires to a voltmeter at the top.

Fe2++2e−→Fe(s)E0=−0.44V\mathrm{Fe^{2+} + 2e^- \rightarrow Fe_{(s)}} \qquad \mathrm{E^0 = -0.44V}

Ag++e−→Ag(s)E0=0.80V\mathrm{Ag^+ + e^- \rightarrow Ag_{(s)}} \qquad \mathrm{E^0 = 0.80V}

What is the potential (in volts) of the above system?

  • 1.21
  • 1.24
  • 1.27
  • 2.01
  • 2.07

Отговори

Решение

Оригинал в Архива: iom-2021-blitz-tasks-eng.pdf · официални решения: iom-2021-blitz-answers-eng.pdf