OPhO 2026, Единствен кръг — Задача 18. Farampere
2026 Online Physics Olympiad · 21 август 2026 г.
Last updated
Last updated: 22nd August 03:35 UTC
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Corrections (all times are in UTC)
- Q8: Cleared up wording (21/08 04:40 and 04:52)
- Q3: improved wording (21/08 08:49)
- Q19: Improved wording (21/08 09:42)
- Q16: Attempts reset (21/08 22:00), Error bound increased (22/8 02:30)
- Q1: Improved wording (22/08 03:35)
Указания
Format. The OPhO is a team-based competition (3 members at most per team). Unlike previous years, the 2026 OPhO consists of a single round held from August 21, 12 am (UTC), to August 23, 11:59 pm (UTC). The contest is made up of three parts, all running concurrently over the full contest window:
- Short Answer — problems requiring numerical answers, submitted on the OPhO portal;
- Long Answer — problems requiring full written solutions, submitted on the OPhO portal;
- Simulation — computational problems requiring teams to run a provided executable locally, with solutions submitted on the OPhO portal.
All teams have access to all three parts for the entire duration of the contest. Submissions are made on the OPhO portal https://opho.physoly.org/ using the team login, and may be made at any time within the contest window.
Short Answer. Teams submit numerical answers on the portal, with up to three attempts per problem. Every answer submission must be accompanied by a file upload, on the portal, of the working used to obtain that answer. This working will not be graded, but submissions without it will not be accepted. The base score for each problem depends on the number of teams that successfully answer it, each incorrect attempt multiplies the base score by a factor of 0.8, and there is no time factor. The score for an individual problem follows:
where represents whether a team got it on the first, second, or third try, represents the number of teams that answer the problem correctly, and is the sum of across all teams that have solved the problem. The base score is independent of problem number, but expect questions to be ordered roughly by difficulty. A team’s raw Short Answer total is the sum of these values, and all raw totals are then scaled linearly such that the top team receives 55 points.
Long Answer. Teams submit full solutions on the portal. Rubrics are predetermined, and solutions will be reviewed to determine the proper number of points to give. The points breakdown is given per problem, for a total of 35 points. It is recommended that participants write their solutions in LaTeX. Handwritten solutions (or a combination of both) are accepted too; if participants have more than one photo of a handwritten solution (jpg, png, etc.), it is required that they be organized in the correct order in a pdf before submitting.
Simulation. Teams will need to be able to run a provided executable locally. Solutions are submitted on the portal and will be graded against predetermined rubrics. The points breakdown is given per problem, for a total of 10 points.
Scoring. A team’s cumulative score is the sum of its scaled Short Answer score (out of 55 points), Long Answer score (out of 35 points), and Simulation score (out of 10 points), for a maximum score of 100 points.
Permitted Resources. Use of the internet is allowed, including textbooks, published papers, calculators, and computer algebra systems. However, the use of AI tools of any kind is strictly prohibited. This includes, but is not limited to, large language models (e.g. ChatGPT, Claude, Gemini), AI coding assistants, AI-generated search summaries, and any other AI-powered assistance.
Dishonest Behavior. Please refrain from cheating in any form. This includes, but is not limited to, creating alternate accounts to gain additional attempts, sharing answers with other teams, posting problems online, utilizing AI tools as described above, or employing any other method to gain an unfair advantage.
We have previously caught numerous teams engaging in such practices, and pursuing dishonest tactics provides no genuine sense of security. Any teams found to be acting maliciously will be notified via email, along with the opportunity to appeal. Failing to provide a valid appeal will result in a ban from participating in any future Physoly competitions. Our utmost priority is to ensure an enjoyable contest experience for all participants, and we remain committed to preventing any disruption to the fun for others.
Awards and Results. The top competitors will be recognized on the website. No cash prizes will be awarded this year.
List of Constants
- Proton mass,
- Neutron mass,
- Electron mass,
- Avogadro’s constant,
- Universal gas constant,
- Boltzmann’s constant,
- Electron charge magnitude,
- 1 electron volt,
- Speed of light,
- Universal Gravitational constant,
- Solar Mass
- Acceleration due to gravity,
- 1 unified atomic mass unit,
- Planck’s constant,
- Permittivity of free space,
- Coulomb’s law constant,
- Permeability of free space,
- Magnetic constant,
- 1 atmospheric pressure,
- Wien’s displacement constant,
- Stefan-Boltzmann constant,
Условие
Consider a hollow metallic ring torus of mean radius and tube thickness , with . A wedge of the torus is cut out and displaced outward, along its own line of symmetry, by a distance (see the figures below). We call the displaced quarter and the remaining three-quarter arc .

Each piece is wired as a bent coaxial line. A uniform current runs along the toroidal (outer) surface in the directions shown, and at each open end radial spokes hand it off to an inner wire of radius running along the axial circle, so that within both and the current closes on itself. An external source drives the current at a common time-rate . Find the interaction force between and arising from the changing current.
For a numerical estimate, take , , , , and ; Use a negative sign if the force is attractive (the pieces pull together) and a positive sign if it is repulsive.
Отговори
The official solution gives only this expression; no numerical value is printed.
Решение
Let be the radial distance inside the tube. Inside the tube, the magnetic field is:
Thus, the electric field inside the tube is given by (via Faraday’s law):
This is the electric field directed along the arc of the cable thingy. Because the field runs along the cable and stops at the two ends, there must be some buildup of charge. By Gauss law,
This reduces the problem to finding the interaction force between 4 point charges, as we may neglect higher order multipole terms in the force. Each diagonal pair of point charges is apart. The two near pairs are separated by . These pairs have opposite charges, so they contribute an attractive force . The diagonal pairs have the same sign, so the two pairs contribute a repulsive force . Adding them together, we obtain,
Оригинал в Архива: problems.pdf · официални решения: solutions.pdf