OWAO 2025, Теория — Задача 6. Glimpse of GLIMPSE

2025 ◇ Theoretical Round ◇ Problems

Внимание: Бележка към темата

All eight whole original tasks and 29 lettered parts, complete official worked solutions, alternatives and marking schemes are retained. Constants are native question page 5 and repeated key page 31, fully transcribed once as a shared reference. No paper/time/task/part total is printed, so no totals are inferred from marking criteria. Source mathematical/subscript/endpoint/equality discrepancies are preserved with attributed local notes. The separately printed cooler-star Criterion (x) remains inside original task 8; no extra problem is created.

Константи

Universal

Gravitational constantG=6.67⋅10−11 m3/(kg⋅s2)G=6.67\cdot10^{-11}\ \mathrm{m^3/(kg\cdot s^2)}
Speed of lightc=3.00⋅108 m/sc=3.00\cdot10^8\ \mathrm{m/s}
Planck constanth=6.63⋅10−34 J⋅sh=6.63\cdot10^{-34}\ \mathrm{J\cdot s}
Boltzmann constantkB=1.38⋅10−23 J/Kk_B=1.38\cdot10^{-23}\ \mathrm{J/K}
Gas constantR=8.314 J/(mol⋅K)\mathfrak R=8.314\ \mathrm{J/(mol\cdot K)}
Proton massmp=1.673⋅10−27 kgm_p=1.673\cdot10^{-27}\ \mathrm{kg}

Astronomical

Astronomical unit1 au=149.6⋅106 km1\ \mathrm{au}=149.6\cdot10^6\ \mathrm{km}
Parsec1 pc=206265 au1\ \mathrm{pc}=206265\ \mathrm{au}
Hubble constantH0=70 (km/s)/MpcH_0=70\ \mathrm{(km/s)/Mpc}

Earth

RadiusR⊕=6371 kmR_\oplus=6371\ \mathrm{km}
MassM⊕=5.97⋅1024 kg\mathfrak M_\oplus=5.97\cdot10^{24}\ \mathrm{kg}
Obliquity of eclipticε=23.4∘\varepsilon=23.4^\circ
Surface gravityg=9.81 m/s2g=9.81\ \mathrm{m/s^2}
Orbital periodT⊕=365.26 daysT_\oplus=365.26\ \mathrm{days}
Orbital eccentricitye⊕=0.0167e_\oplus=0.0167

Hydrogen spectrum

Lyman Lα\mathrm L\alphaλLα=1215.7 A˚\lambda_{\mathrm L\alpha}=1215.7\ \text{Å}
Balmer Hα\mathrm H\alphaλHα=6562.8 A˚\lambda_{\mathrm H\alpha}=6562.8\ \text{Å}

Jupiter

RadiusRJ=6.99⋅104 kmR_J=6.99\cdot10^4\ \mathrm{km}
MassMJ=1.90⋅1027 kg\mathfrak M_J=1.90\cdot10^{27}\ \mathrm{kg}
Orbital radiusaJ=5.20 aua_J=5.20\ \mathrm{au}
Orbital periodTJ=11.86 yrT_J=11.86\ \mathrm{yr}

Sun

RadiusR⊙=6.96⋅105 kmR_\odot=6.96\cdot10^5\ \mathrm{km}
MassM⊙=1.99⋅1030 kg\mathfrak M_\odot=1.99\cdot10^{30}\ \mathrm{kg}
Absolute magnitudeM⊙=4.74m (bol.)M_\odot=4.74^{\mathrm m}\ \text{(bol.)}
Effective temperatureT⊙=5.8⋅103 KT_\odot=5.8\cdot10^3\ \mathrm K
LuminosityL⊙=3.828⋅1026 WL_\odot=3.828\cdot10^{26}\ \mathrm W
Color index(B−V)⊙=+0.65m(B-V)_\odot=+0.65^{\mathrm m}

Emission constants

Stefan-Boltzmannσ=5.67⋅10−8 W/(m2⋅K4)\sigma=5.67\cdot10^{-8}\ \mathrm{W/(m^2\cdot K^4)}
Wien’s displacementb=2898 μm⋅Kb=2898\ \mathrm{\mu m\cdot K}

UBV… system — Mean wavelengths

U bandλU=364 nm\lambda_U=364\ \mathrm{nm}
B bandλB=442 nm\lambda_B=442\ \mathrm{nm}
V bandλV=540 nm\lambda_V=540\ \mathrm{nm}
K bandλK=2190 nm\lambda_K=2190\ \mathrm{nm}

Условие

The cluster GLIMPSE-C01 is located in the Milky Way. The tip of the red giant branch (TRGB) corresponds to an apparent magnitude of K=8.7mK=8.7^{\mathrm m}. Its absolute magnitude, assuming a metallicity of [Fe/H]=−1.5[\mathrm{Fe/H}]=-1.5, is MK=−6.1mM_K=-6.1^{\mathrm m} (Ivanov et al., 2005).

a) Assuming the extinction is aK=0.45 mag/kpca_K=0.45\ \mathrm{mag/kpc}, estimate the distance to the cluster.

b) Estimate the total extinction AVA_V in the VV band, given the cluster’s Galactic coordinates: latitude b=0∘b=0^\circ, longitude l=31∘l=31^\circ.

NOTE. According to Rieke & Lebofsky (1985), aV/aK=9a_V/a_K=9.

c) In reality, the extinction, even in the KK band, is uncertain: aK=0.45±0.08 mag/kpca_K=0.45\pm0.08\ \mathrm{mag/kpc}. Find the uncertainty in the distance.

d) Is this cluster more likely a globular cluster or an open cluster? Explain.

Отговори

Решение

Теми и трудност

Оценена трудност: 3/5.

Светлина и астрономически измервания · Галактики и космология · Междузвездно поглъщане · Звездни величини · Млечен път

Предпоставки: Гимназиална подготовка, Разширена олимпиадна подготовка


Оригинал в Архива: OWAO_2025_Theoretical_Problems.pdf · официални решения: OWAO_2025_Theoretical_Solutions.pdf