USAAAO 2026, I кръг — Задача 13
USAAAO 2026 - First Round · 9 февруари 2026 г.
Problem writers
Problem writers: Srihari (Hari) Balaji, Vincent Bian, Ferdinand, Hagan Hensley, Elizabeth Lee, Joe McCarty, Lucas Pinheiro, Feodor Yevtushenko
Условие
What is the smallest angular separation between Algol ( Per) and the Sun throughout the year? Algol’s declination is , and its right ascension is 3h08min.
(a) .
(b) .
(c) .
(d) .
(e) .
Отговори
- C
Решение
Solution: The Sun moves along the ecliptic throughout the year. Therefore, the minimum angular separation between the Sun and Algol corresponds simply to Algol’s ecliptic latitude. The figure below shows the spherical triangles that can be used to obtain the coordinate conversion formulas between the equatorial coordinates and the ecliptic coordinates.

In the figure, denotes the right ascension, denotes the declination, denotes the ecliptic longitude, denotes the ecliptic latitude, and denotes the obliquity of the ecliptic.
Using the spherical law of cosines on the triangle:
Answer: C
Оригинал в Архива: usaaao_first_exam_2026.pdf · официални решения: usaaao_first_exam_solutions_2026.pdf