USAPhO 2007, Полуфинал — Задача 4. A4
AAPT AIP United States Physics Team 2007 — 2007 Semi-Final Exam · 25 т.
Указания
DO NOT OPEN THIS TEST UNTIL YOU ARE TOLD TO BEGIN
Work Part A first. You have 90 minutes to complete all four problems.
After you have completed Part A, you may take a break.
Then work Part B. You have 90 minutes to complete both problems.
Show all your work. Partial credit will be given.
Start each question on a new sheet of paper. Be sure to put your name in the upper right-hand corner of each page, along with the question number and the page number/total pages for this problem. For example,
Doe, Jamie
A1 – 1/3
A hand-held calculator may be used. Its memory must be cleared of data and programs. You may use only the basic functions found on a simple scientific calculator. Calculators may not be shared. Cell phones, PDA’s, or cameras may not be used during the exam or while the exam papers are present. You may not use any tables, books, or collections of formulas.
Questions with the same point value are not necessarily of the same difficulty.
Do not discuss the contents of this exam with anyone until after March 27th.
Good luck!
Possibly Useful Information - (Use for both part A and for part B)
| Gravitational field at the Earth’s surface | |
| Newton’s gravitational constant | |
| Coulomb’s constant | |
| Biot-Savart constant | |
| Speed of light in a vacuum | |
| Boltzmann’s constant | |
| Avogadro’s number | |
| Ideal gas constant | |
| Stefan-Boltzmann constant | |
| Elementary charge | |
| 1 electron volt | |
| Planck’s constant | |
| Electron mass | |
| Binomial expansion | for |
| Small angle approximations | ; |
Условие
A nonlinear circuit element can be made out of a parallel plate capacitor and small balls, each of mass , that can move between the plates. The balls collide inelastically with the plates, dissipate all kinetic energy as thermal energy, and immediately release the charge they are carrying to the plate. Almost instantaneously, the balls then pick up a small charge of magnitude from the plate; the balls are then repelled directly toward the other plate under electrostatic forces only. Another collision happens, kinetic energy is dissipated, the balls give up the charge, collect a new charge, and the cycle repeats. There are balls per unit surface area of the plate. The capacitor has a capacitance . The separation between the plates is much larger than the radius of the balls. A battery is connected to the plates in order to maintain a constant potential difference . Neglect edge effects and assume that magnetic forces and gravitational forces may be ignored.
a. Determine the time it takes for one ball to travel between the plates in terms of any or all of the following variables: , , , and . [5 т.]
b. Calculate the kinetic energy dissipated as thermal energy when one ball collides inelastically with a plate surface in terms of any or all of the following variables: , , , and . [5 т.]
c. Derive an expression for the current between the plates in terms of the permittivity of free space, , and any or all of the following variables: , , , , and . [5 т.]
d. Derive an expression for the effective resistance of the device in terms of , and any or all of the following variables: , , , , and . [5 т.]
e. Calculate the rate at which the kinetic energy of the balls is converted into thermal energy in terms of , and any or all of the following variables: , , , , and . [5 т.]
Отговори
a.
b.
c.
d.
e.
As printed in the official solution (A4-8): ε0 appears in the numerator of the final expression, while the preceding step gives C/ε0; the printed form is kept verbatim.
Решение
a. The electric field between the plates is given by . The force on the charged ball is then . The acceleration of the ball is .
Kinematics gives us for the time of flight. So
b. The kinetic energy collected by a ball will be as it moves between the plates. That’s what will be dissipated.
c. The current is given by . The total number of balls is , where is the surface area of a plate. The charge is then , so the current is
We can’t stop here, since this is not in terms of the allowed variables. The problem is and , but since , we have
d. , so
We can simplify, slightly, with
e. , so
Оригинал в Архива: olympiad_2007_semi-final.pdf · официални решения: olympiad_2007_semi-final_soln.pdf